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我正在使用JQuery验证插件。我得到了远程函数与默认的PHP文件。JQuery验证远程和检查数据库PHP MySQL错误
我修改了PHP文件用我自己的版本,但MySQL是返回
Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /home/fastbluf/syatch/module/1.func.php on line 15
我的PHP代码如下。我的所有语法看起来都正确
<?php
// Last Edited: 4/23/12
$conn = mysql_connect('localhost','hidden','hidden') or die('Iam dying');
$rs = @mysql_select_db("hidden", $conn) or die("Err:Db");
$do = $_REQUEST['do'];
$email= $_REQUEST['email'];
$user= $_REQUEST['user'];
function checkInfo($do,$email,$user){
switch ($do) {
case 1:
$sql = "select * from User_Base where Email_Address = $email";
$results = mysql_query($sql). mysql_error();
$nResults = mysql_num_rows($results);
if ($nResults > 0) {
$valid="false";
} else {
$valid="true";
}
break;
case 2:
//not yet
break;
}
return $valid;
}
echo checkInfo($do,$email,$user);
?>
谢谢。很多..甚至没有跟踪真正的逃生字符串..病必须实现,无处不在现在.. – Ray 2012-04-23 19:09:27
没问题,很高兴我可以帮助:) – Developer 2012-04-23 19:09:55