显示一些数组和多维数组一起

Question

下面是变量：

$ids = array_unique($_POST['id']); 
$total_ids = count($ids); 

$name = $_POST['name']; 

$positions = $_POST['position']; 
$total_positions = count($positions); 

这是什么的print_r显示：

[id] => Array ( 
    [0] => 3 
    [1] => 7) 

[name] => Array ( 
    [0] => George 
    [1] => Barack) 

[position] => Array ( 
    [1] => Array ( 
     [0] => 01 
     [1] => 01) 
    [2] => Array ( 
     [0] => 01 
     [1] => 01 
     [2] => 01)) 

这就是我想获得刷新结果/提交：

[id][0]; 
    [name][0]; 
     [position][1][0];[position][1][1] 
[id][1]; 
    [name][1]; 
     [position][2][0];[position][2][1];[position][2][2] 

为了使通缉的结果以及明确：

User with [id][0] 
    is called [name][0] 
     and works at [position][1][0];[position][1][1] 
BUT 

User with [id][1] 
    is called [name][1]; 
     and works at [position][2][0];[position][2][1];[position][2][2] 

请注意，[position] s以[1]开头，而不是[0]。

我该如何显示数组的顺序？

Answer 1

我不是100％肯定，我知道你需要什么，而是试图以匹配显示输出的最终的例子，我想出了以下内容：

// iterate through each of the `$ids` as a "user" 
foreach ($ids as $key => $value) { 
    // output the user's ID 
    echo 'User with ' . $value; 
    if (isset($name[$key])) { 
     // output the user's name 
     echo ' is called ' . $name[$key]; 
    } 
    if (isset($position[$key + 1])) { 
     // output a ';'-delimited list of "positions" 
     echo ' and works at '; 
     $positions = ''; 
     // the `$positions` array starts with index 1, not 0 
     foreach ($position[$key + 1] as $pos) { 
      $positions .= (($positions != '') ? ';' : '') . $pos; 
     } 
     echo $positions; 
    } 
    echo '<br />'; 
} 

这会给输出类似于：

用户用1被称为比尔和POS1工程; POS2，POS3
用户有14名为吉尔和pos134

工作