我正在尝试围绕我的公司正在开发的API进行封装。这是安宁的,使用邮递员,我可以发送邮件请求到像http://subdomain.dev.myapi.com/api/v1/auth/
这样的端点,用户名和密码为POST数据,并且我收到一个令牌。所有按预期工作。现在,当我尝试从PHP执行相同的操作时,我得到一个GuzzleHttp\Psr7\Response
对象,但似乎无法像在邮递员请求中那样在其内部的任何位置找到该令牌。Guzzlehttp - 如何从Guzzle 6获得响应的身体?
相关的代码如下所示:
$client = new Client(['base_uri' => 'http://companysub.dev.myapi.com/']);
$response = $client->post('api/v1/auth/', [
'form_params' => [
'username' => $user,
'password' => $password
]
]);
var_dump($response); //or $resonse->getBody(), etc...
以上代码的输出看起来像(警告,文字的传入墙):
object(guzzlehttp\psr7\response)#36 (6) {
["reasonphrase":"guzzlehttp\psr7\response":private]=>
string(2) "ok"
["statuscode":"guzzlehttp\psr7\response":private]=>
int(200)
["headers":"guzzlehttp\psr7\response":private]=>
array(9) {
["connection"]=>
array(1) {
[0]=>
string(10) "keep-alive"
}
["server"]=>
array(1) {
[0]=>
string(15) "gunicorn/19.3.0"
}
["date"]=>
array(1) {
[0]=>
string(29) "sat, 30 may 2015 17:22:41 gmt"
}
["transfer-encoding"]=>
array(1) {
[0]=>
string(7) "chunked"
}
["content-type"]=>
array(1) {
[0]=>
string(16) "application/json"
}
["allow"]=>
array(1) {
[0]=>
string(13) "post, options"
}
["x-frame-options"]=>
array(1) {
[0]=>
string(10) "sameorigin"
}
["vary"]=>
array(1) {
[0]=>
string(12) "cookie, host"
}
["via"]=>
array(1) {
[0]=>
string(9) "1.1 vegur"
}
}
["headerlines":"guzzlehttp\psr7\response":private]=>
array(9) {
["connection"]=>
array(1) {
[0]=>
string(10) "keep-alive"
}
["server"]=>
array(1) {
[0]=>
string(15) "gunicorn/19.3.0"
}
["date"]=>
array(1) {
[0]=>
string(29) "sat, 30 may 2015 17:22:41 gmt"
}
["transfer-encoding"]=>
array(1) {
[0]=>
string(7) "chunked"
}
["content-type"]=>
array(1) {
[0]=>
string(16) "application/json"
}
["allow"]=>
array(1) {
[0]=>
string(13) "post, options"
}
["x-frame-options"]=>
array(1) {
[0]=>
string(10) "sameorigin"
}
["vary"]=>
array(1) {
[0]=>
string(12) "cookie, host"
}
["via"]=>
array(1) {
[0]=>
string(9) "1.1 vegur"
}
}
["protocol":"guzzlehttp\psr7\response":private]=>
string(3) "1.1"
["stream":"guzzlehttp\psr7\response":private]=>
object(guzzlehttp\psr7\stream)#27 (7) {
["stream":"guzzlehttp\psr7\stream":private]=>
resource(40) of type (stream)
["size":"guzzlehttp\psr7\stream":private]=>
null
["seekable":"guzzlehttp\psr7\stream":private]=>
bool(true)
["readable":"guzzlehttp\psr7\stream":private]=>
bool(true)
["writable":"guzzlehttp\psr7\stream":private]=>
bool(true)
["uri":"guzzlehttp\psr7\stream":private]=>
string(10) "php://temp"
["custommetadata":"guzzlehttp\psr7\stream":private]=>
array(0) {
}
}
}
从邮差的输出是这样的:
{
"data" : {
"token" "fasdfasf-asfasdfasdf-sfasfasf"
}
}
很明显我错过了一些关于使用响应对象的问题zzle。 Guzzle响应表明请求中有200个状态码,所以我不确定我需要做什么来检索返回的数据。
'$响应 - > getBody() - > getContents()'不工作? – Federkun
你美丽的天才@Leggendario。你在你自己的时代是一个传奇。我不知道我以前没有找到'getContents()'。 – Greg