我试图通过套接字发送大文件。该程序适用于小文件(如html页面或pdf),但是当我发送超过3/4 mb的文件时,输出总是被损坏(使用文本编辑器查看它,我注意到最后几行总是丢失)。通过套接字发送大文件时出错
这里是服务器的代码:
BufferedInputStream in = null;
FileOutputStream fout = null;
try {
server = new ServerSocket(port);
sock = server.accept();
in = new BufferedInputStream(sock.getInputStream());
setPerc(0);
received = 0;
int incByte = -1;
fout = new FileOutputStream(path+name, true);
long size = length;
do{
int buffSize;
if(size >= 4096){
buffSize = 4096;
}else{
buffSize = 1;
}
byte[] o = new byte[buffSize];
incByte = in.read(o, 0, buffSize);
fout.write(o);
received+=buffSize;
setPerc(calcPerc(received, length));
size -= buffSize;
//d("BYTE LETTI => "+incByte);
}while(size > 0);
server.close();
} catch (IOException e) {
e("Errore nella ricezione file: "+e);
}finally{
try {
fout.flush();
fout.close();
in.close();
} catch (IOException e) {
e("ERRORE INCOMINGFILE");
}
}
pr.release(port);
而这里的客户端代码:
FileInputStream fin = null;
BufferedOutputStream out = null;
try {
sock = new Socket(host, port);
fin = new FileInputStream(file);
out = new BufferedOutputStream(sock.getOutputStream());
long size = file.length();
int read = -1;
do{
int buffSize = 0;
if(size >= 4096){
buffSize = 4096;
}else{
buffSize = (int)size;
}
byte[] o = new byte[buffSize];
for(int i = 0; i<o.length;i++){
o[i] = (byte)0;
}
read = fin.read(o, 0, buffSize);
out.write(o);
size -= buffSize;
//d("BYTE LETTI DAL FILE => "+read);
}while(size > 0);
} catch (UnknownHostException e) {
} catch (IOException e) {
d("ERRORE NELL'INVIO DEL FILE: "+e);
e.printStackTrace();
}finally{
try {
out.flush();
out.close();
fin.close();
} catch (IOException e) {
d("Errore nella chiusura dei socket invio");
}
}
我觉得它的东西与缓冲区的大小有关,但我想不出这里有什么问题。
永远不要依赖'File.length()'提供的文件大小,而只是继续阅读直到完成。应该使用'File.length()'作为它可能有多大的概念。 –