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我收到此错误,我需要一些帮助。 我一直被困在这个很长一段时间,我感觉好像问题在我的脸上。“字段列表”中的未知列'problem_id'
这是我的数据库结构。我使用的MySQL
mysql> describe user_supplied_problem_solution;
+------------+------------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+------------+------------------+------+-----+---------+----------------+
| id | int(10) unsigned | NO | PRI | NULL | auto_increment |
| user_id | int(10) unsigned | NO | MUL | NULL | |
| problem_id | int(10) unsigned | NO | MUL | NULL | |
| solution | text | NO | | NULL | |
+------------+------------------+------+-----+---------+----------------+
这是运行时,我收到错误的PHP代码:
public function createSolution($description, $user_id, $part_order = NULL) {
$solution_id = NULL;
if(!isset($part_order)) {
print("running the problem level query\n"); // Debug
$query = "INSERT INTO user_supplied_problem_solution (problem_id, user_id, solution)
VALUES (:problem_id, :user_id, :solution)";
} else {
print("running the part level query\n"); // Debug
$query = "INSERT INTO user_supplied_part_solution (user_id, part_id, solution)
VALUES (:user_id, :part_id, :solution)";
}
$this->dbh->beginTransaction();
try {
$statement = $this->dbh->prepare($query);
if(!isset($part_order)) {
print($query . PHP_EOL); // Debug
print("running the problem level binding\n"); // Debug
print("The problem ID is $this->problem_id\n"); // Debug
$statement->bindParam(':problem_id', $this->problem_id, PDO::PARAM_INT);
} else {
// Get the part_id
$part_id = $this->getPartIdFromOrder($part_order);
if(!$part_id) {
// Part_id does not exist -- rollback and return
$this->dbh->rollBack();
return false;
}
$statement->bindParam(':part_id', $part_id, PDO::PARAM_INT);
}
$statement->bindParam(':user_id', $user_id, PDO::PARAM_INT);
$statement->bindParam(':solution', $description, PDO::PARAM_STR);
$statement->execute();
$solution_id = $this->dbh->lastInsertId();
} catch(PDOException $e) {
$this->dbh->rollBack();
print_r($e->errorInfo); // Debug
return false;
}
$this->dbh->commit();
describe user_supplied_problem_solution;
注(调试)print
命令我把我留在了向您展示执行代码。这是构造时正确创建$this->dbh
的对象的一部分。我通过命令行运行了这个查询,并且它成功了。这是我的输出:
mysql> INSERT INTO user_supplied_problem_solution (problem_id, user_id, solution)
-> VALUES (130, 40, "Solution");
Query OK, 1 row affected (0.00 sec)
这是我当我跑上面的方法签名createSolution("this is a test solution", 40)
代码:
running the problem level query
INSERT INTO user_supplied_problem_solution (problem_id, user_id, solution)
VALUES (:problem_id, :user_id, :solution)
running the problem level binding
The problem ID is 130
Array
(
[0] => 42S22
[1] => 1054
[2] => Unknown column 'problem_id' in 'field list'
)
我多久,这是道歉,但我知道的第一反应像这样的问题是人们需要更多信息。
确实选择该字段,使用PHP正常工作。您应该通过PHP运行您的描述查询并打印结果。是否有可能你有一个你连接到数据库的副本..等等,你必须验证PHP正在获得的结构。 – ArtisticPhoenix
这是一个漫长的过程,但您使用PHP的用户是否拥有适当的权限。否则一切看起来很好。 – ArtisticPhoenix
您确定在代码中访问与手动测试相同的数据库吗? – MaxZoom