2013-04-22 154 views
1

你好同行的程序员:)。我是非常新的Java,如果这是PHP我已经这样做:P,无论如何,我试图在这里搜索所有答案(stackoverflow),但没有一个适合我的具体问题,或者我没有看到一个例如,我错过了某些东西......无论如何,如果你知道任何类似于我的问题的解决方案,请张贴链接到答案。Java添加元素的属性到xml文件

确定的问题;)

我有这样的XML文件中的,我需要它,就像这样:

<?xml version="1.0" encoding="UTF-8"?> 
<events> 
    <event id="46" title="Ferias" start="2013-04-25" end="2013-04-26" allDay="false" editable="true"/> 
    <event id="47" title="Falta" start="Wed Apr 17 2013 00:00:00 GMT+0100" end="Thu Apr 18 2013 00:00:00 GMT+0100" allDay="false" editable="true"/> 
    <event id="48" title="Tolerancia de Ponto" start="Mon Apr 01 2013 00:00:00 GMT+0100" end="" allDay="false" editable="true"/>  
    <event id="49" title="Titulo teste" start="Thu Apr 11 2013 00:00:00 GMT+0100" end="Sat Apr 13 2013 00:00:00 GMT+0100" allDay="true" editable="true"/> 
    <event id="50" title="dfgfdgf" start="Fri Apr 12 2013 00:00:00 GMT+0100" end="Sat Apr 13 2013 00:00:00 GMT+0100" allDay="true" editable="true"/> 
    <event id="51" title="hghfjfghj" start="Tue Apr 16 2013 00:00:00 GMT+0100" end="Wed Apr 17 2013 00:00:00 GMT+0100" allDay="true" editable="true"/> 
    <event id="52" title="grande evento" start="Tue Apr 23 2013 00:00:00 GMT+0100" end="Wed May 01 2013 00:00:00 GMT+0100" allDay="true" editable="true"/> 
</events> 

,我尝试添加新的元素“事件”与atributes,我用这个来加载和修改:

 String FilePath = "D:/myxml.xml"; 
    Document doc = openXMLfile(FilePath); 

其未装入这里的问题..

,其中openXMLfile是这样的:

protected Document openXMLfile(String filepath){ 
    Document doc = null; 
    try { 
     File fXmlFile = new File(filepath); 
     DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance(); 
     DocumentBuilder dBuilder = dbFactory.newDocumentBuilder(); 
     doc = dBuilder.parse(fXmlFile);   
    } catch (Exception e) { 
     e.printStackTrace(); 
    } 
    return doc; 
} 

然后在我的函数添加元素我这样做:

File file = new File("D:\myxml.xml"); 
Element event = doc.createElement("event"); 
    event.setAttribute("test","testvalue"); 
    doc.getDocumentElement().appendChild(event); 

    filePutContents(doc,file); 

其中filePutContents我有这样的功能:

protected void filePutContents(Document doc,File file){ 
    try{      
     TransformerFactory tFactory = TransformerFactory.newInstance(); 
     Transformer transformer = tFactory.newTransformer();  
     transformer.setOutputProperty(OutputKeys.INDENT,"yes"); 

     DOMSource source = new DOMSource(doc); 
     //StreamResult result = new StreamResult(System.out);//problem was this 
     StreamResult result = new StreamResult(file);//correct way 
       transformer.transform(source, result); 

    }catch(TransformerConfigurationException tce){ 
     /*ERRO do Transformer*/   
     System.out.println("* Transformer Factory error"); 
     System.out.println(" " + tce.getMessage()); 

     Throwable x = tce; 
     if (tce.getException() != null) 
      x = tce.getException(); 
      x.printStackTrace(); 
    }catch(TransformerException te){ 
     /*ERRO da Factory*/ 
     System.out.println("* Transformation error"); 
     System.out.println(" " + te.getMessage()); 

     Throwable x = te; 
     if (te.getException() != null) 
      x = te.getException(); 
      x.printStackTrace(); 
    } 
} 

的问题是,没有元素被添加到文件中,我希望文件被更新,我做错了什么?谢谢

代码问题解决了,我反映的变化;)谢谢做佣工:)

+0

问题是什么? – Kishore 2013-04-22 10:36:49

回答

1
StreamResult result = new StreamResult(System.out); 

上面的语句是指导你的输出到控制台(System.out的)。如果你想要更新文件,将它指向文件。

尝试这个 -

StreamResult result = new StreamResult(new FileOutputStream("somefile.xml")); 
+0

我试过了: File file = new File(filepath); StreamResult result = new StreamResult(file); 和 StreamResult result = new StreamResult(new FileOutputStream(file)); BTW这必须是在尝试捕捉 没有工作:( – 2013-04-22 11:14:29

+0

好完蛋了,我错了做的事情: StreamResult结果=新的StreamResult(文件); 做工精细的感谢;) – 2013-04-22 14:11:37