我想在我的应用程序中做撤消功能..为此我搜索了我的网发现,采取x,y点,我已经做了下面的代码我arraylist我无法撤消图纸?如何在Android的绘画应用中实现撤消功能?
public Drawview(Context context, float x, float y, int r) {
super(context);
mBitmap = Bitmap.createBitmap(800, 1200, Bitmap.Config.ARGB_8888);
// mainbitmap.add(mBitmap);
//System.out.println("**mBitmapPaint***"+mBitmapPaint);
mCanvas = new Canvas(mBitmap);
mPath = new Path();
mBitmapPaint = new Paint(Paint.DITHER_FLAG);
}
@Override
protected void onSizeChanged(int w, int h, int oldw, int oldh) {
super.onSizeChanged(w, h, oldw, oldh);
}
@Override
protected void onDraw(Canvas canvas) {
System.out.println("***Drawinglines****"+Drawinglines);
canvas.drawBitmap(mBitmap, 0, 0, mBitmapPaint);
canvas.drawPath(mPath, mPaint);
}
private float mX, mY;
private static final float TOUCH_TOLERANCE = 4;
private void touch_start(float x, float y) {
mPath.reset();
mPath.moveTo(x, y);
mX = x;
mY = y;
}
private void touch_move(float x, float y) {
float dx = Math.abs(x - mX);
float dy = Math.abs(y - mY);
if (dx >= TOUCH_TOLERANCE || dy >= TOUCH_TOLERANCE) {
mPath.quadTo(mX, mY, (x + mX)/2, (y + mY)/2);
mX = x;
mY = y;
}
}
private void touch_up() {
mPath.lineTo(mX, mY);
mCanvas.drawPath(mPath, mPaint);
/// path.
//graphics.add(mPath);
mPath.reset();
}
// events when touching the screen
public boolean onTouchEvent(MotionEvent event) {
event.getAction();
int eventaction = event.getAction();
int X = (int)event.getX();
int Y = (int)event.getY();
switch (eventaction) {
case MotionEvent.ACTION_DOWN:
{
touch_start(X, Y);
}
invalidate();
break;
case MotionEvent.ACTION_MOVE:
System.out.println("***ACTION_MOVE**************"+X+"************"+Y);
if((Drawinglines.equals("Pen"))||(Drawinglines.equals("Erase")))
{
touch_move(X, Y);
temp_point.add(new Point(X,Y));
}
invalidate();
break;
case MotionEvent.ACTION_UP:
main_Points.add(temp_point);
temp_point = null;
touch_up();
invalidate();
break;
}
return true;
}
public void undopath()
{
main_Points.remove(main_Points.size()-1);
invalidate();
}
}
@Override
public void onClick(View v) {
if(v == Undo)
{
Drawview abc=new Drawview();
abc.undopath();
}
但是撤消撤消功能不起作用。
而究竟是什么你有问题吗? – 2012-03-26 13:01:57
我的问题是根据代码我已经使X的Arraylist,y点后,从arraylist元素删除后,我怎么得到这一行main_Points.remove(main_Points.size() - 1);如何得到先前的图纸线 – user1287756 2012-03-26 13:03:25
是啊,但是到目前为止您尝试过的撤销/重做逻辑在哪里?你说:“撤消不工作”,但我没有看到你说的撤消代码不起作用。 – 2012-03-26 13:04:29