生成JSON，只有通过我的产品表中获取最后一行

Question

的列设置像这样在一个名为表“产品”

+------------++---------------++----------------------++---------------++----------------+ 
| product_id | product_name | product_description | product_image | product_price | 
+------------++---------------++----------------------++---------------++----------------+ 
|  1  |  a1   | good    |  url.jpg |  150dkk  | 
+------------++---------------++----------------------++---------------++----------------+ 
|  2  |  a2   | nice    |  url.jpg |  150dkk  | 
+------------++---------------++----------------------++---------------++----------------+ 

当年这里是我的代码，所以我环路和将它们推入一个将成为JSON的数组中。

//Create an array 
    $json_response = json_decode('{"products":[]}'); 

    $sql = "SELECT * FROM products"; 
    $result = $conn->query($sql); 
    while($row = mysqli_fetch_array($result)){ 
    $row_array['id'] = $row['product_id']; 
    $row_array['name'] = $row['product_name']; 
    $row_array['description'] = $row['product_description']; 
    $row_array['image'] = $row['product_image']; 
    $row_array['price'] = $row['product_price']; 
} 
    // Push the columns into the created array 
    array_push($json_response->products, $row_array); 

    // Encode into an object 
    $oJsonResponse = json_encode($json_response); 

    // Save it in a new file that holds the json from MySQL 
    file_put_contents('products.json', $oJsonResponse); 

的问题是，我只是设法让与的2号产品进入我的JSON文件，因此在第一个产品永远不会保存在以.json文件的。当我做echo = "$row[product_name]"; - 我得到这两个产品

Answer 1

在这里你去（移动array_push到while循环）

<?php 

//Create an array 
$json_response = array(); 

$sql = "SELECT * FROM products"; 
$result = $conn->query($sql); 
while ($row = mysqli_fetch_array($result)) { 
    $row_array['id'] = $row['product_id']; 
    $row_array['name'] = $row['product_name']; 
    $row_array['description'] = $row['product_description']; 
    $row_array['image'] = $row['product_image']; 
    $row_array['price'] = $row['product_price']; 

    // Push the columns into the created array 
    $json_response[] = $row_array; 
} 

// Encode into an object 
$oJsonResponse = json_encode($json_response); 

// Save it in a new file that holds the json from MySQL 
file_put_contents('products.json', $oJsonResponse);