在TAB中显示ListView的问题

从第一个标签切换到第二个标签后出现主要问题。在两个标签中应有所不同列表视图，但似乎这issue我的活动代码：在TAB中显示ListView的问题

public class MainActivity extends Activity { 

    @Override 
    protected void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.activity_main); 

     ActionBar actionBar = getActionBar(); 
     actionBar.setNavigationMode(ActionBar.NAVIGATION_MODE_TABS); 

     ActionBar.Tab tabFirst = actionBar.newTab().setText("First"); 
     ActionBar.Tab tabSecond = actionBar.newTab().setText("Second"); 

     tabFirst.setTabListener(new tabListener()); 
     tabSecond.setTabListener(new tabListener()); 

     actionBar.addTab(tabFirst); 
     actionBar.addTab(tabSecond); 

     } 

    protected class tabListener implements ActionBar.TabListener { 

     ParkFragment firstFragment; 
     ParkFragment secondFragment; 


     @Override 
     public void onTabUnselected(Tab tab, FragmentTransaction ft) { 

     } 

     @Override 
     public void onTabSelected(Tab tab, FragmentTransaction ft) { 
      switch (tab.getPosition()){ 
      case 0: 
       if (firstFragment == null){ 
        firstFragment = new ParkFragment("Here is first url"); 
        ft.add(R.id.parkfragment, firstFragment,"FIRST"); 
       } 
       else{ 
        ft.attach(firstFragment); 
       } 
       break; 

      case 1: 
       if (secondFragment == null){ 
        secondFragment = new ParkFragment("here is the second one"); 
        ft.add(R.id.parkfragment, secondFragment, "SECOND"); 
       } 
       else{ 
        ft.attach(secondFragment); 
       } 
       break; 
      } 
     } 

     @Override 
     public void onTabReselected(Tab tab, FragmentTransaction ft) { 

     } 
    }; 

    public class ParkFragment extends ListFragment { 
     private ArrayList<Cinemas> cinema; 
     private CinemasAdapter cinemaAdapter; 
     private View v; 
     private String url; 

     public ParkFragment (String cinema){ 
      url = cinema; 
     } 

      public void onCreate(Bundle savedInstanceState) { 
      super.onActivityCreated(savedInstanceState); 

      cinema = new Handler().handle(url); 
      cinemaAdapter = new CinemasAdapter(MainActivity.this, R.layout.movie_data_row, cinema); 
      setListAdapter(cinemaAdapter); 

      } 
     }

这里是集装箱XML代码：

<?xml version="1.0" encoding="utf-8"?> 
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" 
    android:layout_width="match_parent" 
    android:layout_height="match_parent" 
    android:baselineAligned="false" 
    android:orientation="vertical" > 

    <FrameLayout 
     android:id="@+id/parkfragment" 
     android:layout_width="fill_parent" 
     android:layout_height="fill_parent" /> 

</LinearLayout>

谢谢您的阅读，任何帮助将不胜感激。

来源

2013-03-19 Andrew Rahimov

您需要添加/附加隐藏另一个片段的片段。

public void onTabSelected(Tab tab, FragmentTransaction ft) { 
     switch (tab.getPosition()){ 
     case 0: 
      if (firstFragment == null){ 
       firstFragment = new ParkFragment("Here is first url"); 
       ft.add(R.id.parkfragment, firstFragment,"FIRST"); 
      } 
      else{ 
       ft.attach(firstFragment); 
      } 
      if (secondFragment != null) 
       ft.hide(secondFragment); 
      break; 

     case 1: 
      if (secondFragment == null){ 
       secondFragment = new ParkFragment("here is the second one"); 
       ft.add(R.id.parkfragment, secondFragment, "SECOND"); 
      } 
      else{ 
       ft.attach(secondFragment); 
      } 
      if (firstFragment != null) 
       ft.hide(firstFragment); 
      break; 
     } 
    }

来源

2013-03-19 08:21:18 Nermeen

同样的事情发生:(也许我必须为每一个片段不同的看法呢？如果是的话，我应该怎么实现，在ParkFragment类？ – 2013-03-19 08:45:30

/** Detaches the androidfragment if exists */ 

       if(secondFragment !=null) 
        ft.detach(secondFragment); 

       /** Detaches the applefragment if exists */ 
       if(firstFragment !=null) 
        ft.detach(firstFragment);

使用这一个分离片段see this

来源

2013-03-19 09:23:22 QuokMoon

在TAB中显示ListView的问题

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