-1
$Game_ID = $Game_Search->Game[$i]->id;
$Game_Info_URL = 'http://thegamesdb.net/api/GetGame.php?id='.$Game_ID;
$Game_Info_Output = simplexml_load_file($Game_Info_URL);
检索数据实例
$Game_Info_Images = $Game_Info_Output->Game->Images;
对于这个问题请参考this URL,我想获得的游戏 - >图像 - >箱艺术A面和Side B.我怎么称呼它?
XML文档(只是必需的字段)
<Data>
<baseImgUrl>http://thegamesdb.net/banners/</baseImgUrl>
<Game>
<Images>
<boxart side="back" width="1518" height="2148" thumb="boxart/thumb/original/back/90-1.jpg">boxart/original/back/90-1.jpg</boxart>
<boxart side="front" width="1530" height="2148" thumb="boxart/thumb/original/front/90-1.jpg">boxart/original/front/90-1.jpg</boxart>
</Images>
</Game>
</Data>
我从来没有做过的DomDocument所以我会等待,看看是否有人对此有何评论为我,我自己的答案似乎更简单... – 2015-02-09 04:41:02
@TimMarshall,是的,你是对的! – felipsmartins 2015-02-09 16:21:07