我正在使用GWTUpload上传文件。 我在onFinishHandler中获取服务器信息,文件名,内容类型等等,但是没有选择从服务器到客户端获取文件内容。如何使用gwtupload从文件中获取文件内容
注:我试图上传XML文件和Excel文件
我使用GWT 2.4,GXT 3.0.1,GWTUpload 0.6.6
这里的示例代码
客户端代码 - OnFinishHandler
u.addOnFinishUploadHandler(new OnFinishUploaderHandler() {
@Override
public void onFinish(IUploader uploader) {
if (uploader.getStatus() == Status.SUCCESS) {
System.err.println(uploader.getServerResponse());
UploadedInfo info = uploader.getServerInfo();
System.out.println("File name " + info.name);
System.out.println("File content-type " + info.ctype);
System.out.println("File size " + info.size);
System.out.println("Server message " + info.message);
}
}
});
servlet代码
public class GWTFileUploadServlet extends UploadAction {
private static final long serialVersionUID = -6742854283091447922L;
String fileContent;
File uploadedFile;
@Override
public String executeAction(HttpServletRequest request,
List<FileItem> sessionFiles) throws UploadActionException {
String response = "";
int cont = 0;
for (FileItem item : sessionFiles) {
if (false == item.isFormField()) {
cont++;
try {
File file = File.createTempFile("upload-", ".bin");
item.write(file);
uploadedFile = file;
fileContent = item.getContentType();
response += "File saved as " + file.getAbsolutePath();
} catch (Exception e) {
throw new UploadActionException(e.getMessage());
}
}
}
removeSessionFileItems(request);
return response;
}
@Override
public void getUploadedFile(HttpServletRequest request,
HttpServletResponse response) throws IOException {
if (fileContent != null && !fileContent.isEmpty()) {
response.setContentType(fileContent);
FileInputStream is = new FileInputStream(uploadedFile);
copyFromInputStreamToOutputStream(is, response.getOutputStream());
} else {
renderXmlResponse(request, response, XML_ERROR_ITEM_NOT_FOUND);
}
}
}
请帮我....
GwtUpload内部使用IOUtils.copy将输入流复制到输出流。我的问题是如何获取正在复制到outputstream的文件内容。 copyFromInputStreamToOutputStream(is,response.getOutputStream()); 我想在OnFinishHandler里面的回应 – Lakshminarayana
你是说你想在客户端读取内容吗? –
是的,我想要的文件内容在客户端 – Lakshminarayana