2015-07-22 86 views
-2
while($record = mysql_fetch_array($myData)){ 
if(($record['Opponent'] == "") && ($record['better_name'] != $_SESSION['user_name'])){ 

    $acceptID = "accept" . $record['bet_ID']; 
    echo "<form action=index.php method=post>"; 
    echo "<input type=submit name=" . $acceptID . " value="ACCEPT">"; 
    echo "<input type=hidden id=" . $record['bet_ID'] . ">"; 
    echo "</form>"; 
} elseif (($record['Opponent'] == "") && ($record['better_name'] == $_SESSION['user_name'])){ 
    echo "<form action=index.php method=post>"; 
    echo "<input type=submit name=delete value=DELETE>"; 
    echo "<input type=hidden id=" . $record['bet_ID'] . ">"; 
    echo "</form>"; 
} else { 
    echo "Game Locked."; 
+0

不清楚,你想要重复表格吗?你面临什么问题? – Jigar

+1

我不明白你的意思是“*按钮*的功能”,究竟是什么?你能否详细说明一下? – Sherif

+2

看起来你忘了告诉我们你有什么问题。 – Ibu

回答

0

我试图通过$_POST['ACCEPT']$_POST['DELETE']命令传递bet_ID。原来,我不需要每个输入/按钮的表单。这对我来说很有效:

## $record['bet_ID'] was pulled from an SQL database table. 


echo "<input type=hidden name=accept value='$record[bet_ID]'>"; 
echo "<input type=submit value=Accept>"; 

$date = $_POST['accept']; 
echo $date;