嗨,你可以请帮我找出任何错误在这个特殊的代码,我是新来PHP时我不知道多少,但错误是
解析错误:语法错误,意外 '$ sql_query'(T_VARIABLE)
<?php
require"init.php";
$user_name = "Nikhil123";
$user_pass = "Sawant"
$sql_query = "select name from user_info where username like '$user_name' and userpass like '$user_pass' ;" ;
$result = mysqli_query($con,$sql_query);
if(mysqli_num_rows($result)>0)
{
$row = mysqli_fetch_assoc($result);
$name = $row("name");
echo "<h3> HELLO welcome".$name "</h3>";
}
else
{
echo "No INFO";
}
?>
谢谢! ,这只是一个愚蠢的错误 –