C＃读取文件解析到数组

Question

我试图读取输入文件到数组中。我的文件看起来像：

00000 * * M010165767HAZZ JONES FAKE乙M12 /十九万六千九百零一分之十六/ 06/2014000000036209 00000 * * M0201657677315 FAKE ST MOON TX56464 485942934维持性

当第一行的第一个单词中的模式与第二行的第二个模块中的模式相匹配时，我希望将整个被空格分隔的行压入数组或对象中。

因此我的数组将包含类似于 [5071177] - > array（[Jones，Fake，B，M12/16/196901，Fake ST，Moon等]）; 完成此操作的最佳方法是什么？

StreamReader sR = new StreamReader("Desktop/records2.txt"); 
StreamWriter sW = new StreamWriter("Desktop/new.txt"); 

while (sR.Peek() != -1) // stops when it reachs the end of the file 
{ 
    string line = sR.ReadLine(); 
    // var myArray = line.Split('\n'); 
    string[] myarray = line.Split(' '); 
    // "line" EDITING GOES HERE 
    sW.WriteLine(myarray);/
} 

Answer 1

首先创建一个类来保存您的数据：

public Record 
{ 
    public string Id { get; set; } 
    public string FirstName { get; set; } 
    public string LastName { get; set; } 
    public string DateOfBirth { get; set; } 
    /* etc */ 
} 

创建一个名为像Parse()返回一个Record另一个类的方法。

public class RecordParser 
{ 
    private List<string> rawRecords; 

    public RecordParser() 
    { 
     rawRecords = new List<string>(); 
    } 

    public RecordParser(string filePath) 
    { 
     rawRecords = new List<string>(); 
     rawRecords.AddRange(ReadLines(filePath)); 
    } 

    public Record Parse(string raw) 
    { 
     // 00000*5071177*M010165767HAZZ JONES FAKE B M12/16/196901/06/2014000000036209 
     string[] myarray = line.Split(' '); 
     Record record = new Record 
     { 
      Id = myarray[0].Split('*')[1], 
      FirstName = myarray[1], 
      LastName = myarray[2], 
      DateOfBirth = myarray[3], 
      /* etc */ 
     }; 
     return record; 
    } 

    public List<Record> ParseAll() 
    { 
     if(!rawRecords.Any()) throw new ArgumentNullException("Nothing to parse."); 

     var records = new List<Record>(); 
     foreach(string raw in rawRecords) 
     { 
      records.Add(Parse(raw)); 
     } 
     return records; 
    } 

    private List<string> ReadLines(string path) 
    { 
     // exception handling needed. 
     return File.ReadLines(path).ToList(); 
    } 
} 

用法：

var recordParser = new RecordParser(); 
string data = "00000*5071177*M010165767HAZZ JONES FAKE B M12/16/196901/06/2014000000036209"; 
Record record = recordParser.Parse(data); 

var recordParser = new RecordParser(@"C://data.txt"); 
List<Record> records = recordParser.ParseAll(); 

Answer 2

File.WriteAllLines(newFile, File.ReadAllLines(oldFile).Select((x) => 
{ 
    var arr = x.Split(' '); 
    var id = arr[0].Split('*')[1]; 
    var spearatedData = string.Join(", ", arr.Skip(0).ToArray()) 
    return string.Format("[{0}] => ({1})", id, spearatedData); 
}));