2017-07-19 45 views
1

下面是我的JPA实体的片段。当我用Hibernate DB2 dialect在JBOSS中运行它时,生成的select查询使用acctYymm而不是ACCT_YYMM导致-206异常。JPA + JBOSS Hibernate NamedQuery不使用列名称

@Column(name = "ACCT_YYMM") 
public String getAcctYymm() { 
    return acctYymm; 
} 

SqlSyntaxErrorException:DB2 SQL错误:SQLCODE = -206,SQLSTATE = 42703,则sqlerrmc = CARTUMLERE0_。 ACCTYYMM,DRIVER = 3.62.56

我试着将命名策略改为EJB3NamingStrategy和DefaultComponentSafeNamingStrategy,它们都没有使用列名。在我实现EmbeddedId并加入两个表之前,我认为这个问题没有发生。会不会有任何关系?

添加我的代码:

两个汽车和池实体份额PK嵌入类

@Embeddable 
public class PK implements Serializable { 
private String acctYymm; 
private String carInit; 
private String carNum; 

@Column(name = "ACCT_YYMM", nullable = false, length = 4) 
public String getAcctYymm() { 
    return acctYymm; 
} 

//skipping getters and setters 

@Column(name = "CAR_INIT", nullable = false, length = 4) 
public String getCarInit() { 
    return carInit; 
} 

@Column(name = "CAR_NUM", nullable = false, length = 6) 
public String getCarNum() { 
    return carNum; 
} 

} 

@Entity 
@NamedQuery(name = "Car.findAll", query = "select umler from CarEntity umler join umler.poolEntity pool where umler.pk.acctYymm = :acctYymm and umler.pk.carInit = :carInit and umler.pk.carNum = :carNum") 
@Table(name = "CART_UMLER", schema = "CARSCHEMA", catalog = "") 
public class CarEntity implements Serializable{ 

@EmbeddedId 
private PK pk = null; 

public PK getPk() { 
    return pk; 
} 

public void setPk(PK pk) { 
    this.pk = pk; 
} 


@OneToOne 
@PrimaryKeyJoinColumns({ 
     @PrimaryKeyJoinColumn(name="ACCT_YYMM", referencedColumnName="ACCT_YYMM"), 
     @PrimaryKeyJoinColumn(name="CAR_INIT", referencedColumnName="CAR_INIT"), 
     @PrimaryKeyJoinColumn(name="CAR_NUM", referencedColumnName="CAR_NUM") 
}) 
private PoolEntity poolEntity; 

private String carTyp; 

@Basic 
@Column(name = "CAR_TYP", nullable = false, length = 1) 
public String getCarTyp() { 
    return carTyp; 
} 

//skipping getters and setters 
} 

@Entity 
@Table(name = "POOL", schema = "CARSCHEMA", catalog = "") 
public class PoolEntity implements Serializable{ 

@EmbeddedId 
private PK pk = null; 

public PK getPk() { 
    return pk; 
} 

public void setPk(PK pk) { 
    this.pk = pk; 
} 

private String poolCd; 

@Basic 
@Column(name = "POOL_CD", nullable = false, length = 7) 
public String getPoolCd() { 
    return poolCd; 
} 

public void setPoolCd(String poolCd) { 
    this.poolCd = poolCd; 
} 

} 

回答

0

如果你仔细看看你的映射,你”你会发现你混合了财产和基于现场的访问。

您需要的@EmbeddedId注释从外地迁移到属性:

private PK pk = null; 

@EmbeddedId 
public PK getPk() { 
    return pk; 
} 

这也适用于PoolEntity poolEntity;PoolEntitypk属性。

您需要对这些映射保持一致,否则,Hibernate不会找到它们。

+0

非常感谢你@ vlad-mihalcea。它工作得很好。我应该阅读一些访问类型。 – Mjasmin

+0

节省一些麻烦并阅读[高性能Java持久性](https://vladmihalcea.com/books/high-performance-java-persistence/)。您只需享受快速运行您的应用程序,不是吗? –

+0

我敢打赌,这值得一读。只是好奇,它有平装版吗?此外,任何计划写一本OpenJPA书籍? :) – Mjasmin