下面是我的JPA实体的片段。当我用Hibernate DB2 dialect在JBOSS中运行它时,生成的select查询使用acctYymm而不是ACCT_YYMM导致-206异常。JPA + JBOSS Hibernate NamedQuery不使用列名称
@Column(name = "ACCT_YYMM")
public String getAcctYymm() {
return acctYymm;
}
SqlSyntaxErrorException:DB2 SQL错误:SQLCODE = -206,SQLSTATE = 42703,则sqlerrmc = CARTUMLERE0_。 ACCTYYMM,DRIVER = 3.62.56
我试着将命名策略改为EJB3NamingStrategy和DefaultComponentSafeNamingStrategy,它们都没有使用列名。在我实现EmbeddedId并加入两个表之前,我认为这个问题没有发生。会不会有任何关系?
添加我的代码:
两个汽车和池实体份额PK嵌入类
@Embeddable
public class PK implements Serializable {
private String acctYymm;
private String carInit;
private String carNum;
@Column(name = "ACCT_YYMM", nullable = false, length = 4)
public String getAcctYymm() {
return acctYymm;
}
//skipping getters and setters
@Column(name = "CAR_INIT", nullable = false, length = 4)
public String getCarInit() {
return carInit;
}
@Column(name = "CAR_NUM", nullable = false, length = 6)
public String getCarNum() {
return carNum;
}
}
@Entity
@NamedQuery(name = "Car.findAll", query = "select umler from CarEntity umler join umler.poolEntity pool where umler.pk.acctYymm = :acctYymm and umler.pk.carInit = :carInit and umler.pk.carNum = :carNum")
@Table(name = "CART_UMLER", schema = "CARSCHEMA", catalog = "")
public class CarEntity implements Serializable{
@EmbeddedId
private PK pk = null;
public PK getPk() {
return pk;
}
public void setPk(PK pk) {
this.pk = pk;
}
@OneToOne
@PrimaryKeyJoinColumns({
@PrimaryKeyJoinColumn(name="ACCT_YYMM", referencedColumnName="ACCT_YYMM"),
@PrimaryKeyJoinColumn(name="CAR_INIT", referencedColumnName="CAR_INIT"),
@PrimaryKeyJoinColumn(name="CAR_NUM", referencedColumnName="CAR_NUM")
})
private PoolEntity poolEntity;
private String carTyp;
@Basic
@Column(name = "CAR_TYP", nullable = false, length = 1)
public String getCarTyp() {
return carTyp;
}
//skipping getters and setters
}
@Entity
@Table(name = "POOL", schema = "CARSCHEMA", catalog = "")
public class PoolEntity implements Serializable{
@EmbeddedId
private PK pk = null;
public PK getPk() {
return pk;
}
public void setPk(PK pk) {
this.pk = pk;
}
private String poolCd;
@Basic
@Column(name = "POOL_CD", nullable = false, length = 7)
public String getPoolCd() {
return poolCd;
}
public void setPoolCd(String poolCd) {
this.poolCd = poolCd;
}
}
非常感谢你@ vlad-mihalcea。它工作得很好。我应该阅读一些访问类型。 – Mjasmin
节省一些麻烦并阅读[高性能Java持久性](https://vladmihalcea.com/books/high-performance-java-persistence/)。您只需享受快速运行您的应用程序,不是吗? –
我敢打赌,这值得一读。只是好奇,它有平装版吗?此外,任何计划写一本OpenJPA书籍? :) – Mjasmin