如何递归地打印每个文件或文件夹的路径名称

Question

这里是我的代码和错误！请给我一个提示

import os 
def traverse(path, d): 
    for item in os.listdir(path): 
     item = os.path.join(path, d) 
     try: 
      traverse(path,d) 
     except: 
      print (path) 

我的错误：

traverse ("test",0) 
Traceback (most recent call last): 
    File "<pyshell#0>", line 1, in <module> 
    traverse ("test",0) 
    File "C:\Users\Phuchu\Desktop\Python\homework8.py", line 65, in traverse 
    for item in os.listdir(path): 
FileNotFoundError: [WinError 3] The system cannot find the path specified: 'test\\*.*' 

Answer 1

你可能更愿意使用os.walk，这是更Python。它会将递归转化为一个简单易懂的循环，并将管理遍历到您的目录中。

Answer 2

使用os.walk

import os 

def traverse(current_dir): 
    for root, dirs, files in os.walk(current_dir): 
     #print all files recursively 
     for file in files: 
      print os.path.join(root,file) 
     #print all folders recursively 
     for dir in dirs: 
      print os.path.join(root,dir)