更新2:显示所有错误和警告
我现在已经移除了PHP文件如下:在php.ini
<?php error_reporting(E_ALL); ?>
我已经设置display_erros如下:
display_errors = On
错误报告在php.ini中设置为以下内容
error_reporting = E_ALL | E_STRICT
重新启动apache后,我仍然没有错误/警告。
UPDATE 1:
我已经改变了从在php.ini使用error_reporting:
的error_reporting = E_ALL & 〜E_DEPRECATED
到
error_reporting = E_ALL | E_STRICT
之后我重新启动apache,
/etc/init.d/apache2重启
,但是网页仍然不会显示任何类型的错误/警告。
原题:
因为$ ERR if语句里面是下面的脚本生成警告。为什么这个警告不会显示在网页浏览器的php页面上?我必须看看Apache日志才能看到警告。此外,如果我delibrately更改“插入到”“删除到”,它不会显示错误的PHP页面上。为什么错误不会显示在实际的php页面上?
<?php
error_reporting(E_ALL);
?>
<html>
<head>
<title></title>
<link rel="icon" type="image/png" href="favicon.ico">
<?php
if($_SERVER['REQUEST_METHOD']=='POST') {
$err = array();
if(empty($_POST['display_name'])) $err[] = "display name field is required";
if(empty($_POST['email'])) $err[] = "email field is required";
if(empty($_POST['password'])) $err[] = "password field is required";
if(!$err) {
try {
$DBH = new PDO("mysql:host=localhost;dbname=database1", "user", "pass");
$DBH -> setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$STH = $DBH -> prepare("delete into table1 (display_name, email, password) values (:display_name, :email, :password)");
$STH -> bindParam(':display_name', $_POST['display_name'], PDO::PARAM_STR, 100);
$STH -> bindParam(':email', $_POST['email'], PDO::PARAM_STR, 100);
$STH -> bindParam(':password', $_POST['password'], PDO::PARAM_STR, 100);
$STH -> execute();
$STH = $DBH -> prepare("delete into table2 (username, status, users_id) values (:username, :status, :users_id)");
$strStatus = 1;
$STH -> bindParam(':username', $_POST['display_name'], PDO::PARAM_STR, 100);
$STH -> bindParam(':status', $strStatus, PDO::PARAM_INT, 1);
$STH -> bindParam(':users_id', $_POST['referer'], PDO::PARAM_INT, 1);
$STH -> execute();
$DBH = null;
} catch(PDOException $e) {
echo $e -> getMessage();
}
header("Location: ".$_SERVER['PHP_SELF']);
exit;
} else {
foreach($_POST as $key => $val) {
$form[$key] = htmlspecialchars($val);
}
}
} else {
$form['display_name'] = $form['email'] = $form['password'] = '';
}
?>
</head>
<body>
<?php foreach($err as $line) { ?>
<div style="error"><?php echo $line; ?></div>
<?php } ?>
<h1>register</h1>
<form method="post">
referers id:<br />
<input type="text" name="referer" /><br /><br />
name:<br />
<input type="text" name="display_name" value="<?php echo $form['display_name']; ?>" /><br /><br />
email:<br />
<input type="text" name="email" value="<?php echo $form['email']; ?>" /><br /><br />
password:<br />
<input type="text" name="password" value="<?php echo $form['password']; ?>" /><br /><br />
<input type="submit" value="register" />
</form>
</body>
</html>
什么是['display_errors'](http://php.net/display_errors)INI设置的当前值? – salathe 2011-03-25 21:00:05
我刚刚检查并将其设置为error_reporting = E_ALL&〜E_DEPRECATED – oshirowanen 2011-03-25 21:05:06
请重新阅读我的问题,我们已经知道您的'error_reporting'设置,因为它在脚本中。 – salathe 2011-03-25 21:15:13