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此公告是从我早期发布的更新(以触发代码)昨日编写复杂的触发
我使用SQL Server 2000中我写的时候现场Applicant.AppStatusRowID
时执行的触发表申请人链接到表位置,表公司&表AppStatus。
我的问题是在我的查询中创建连接。
当Applicant.AppStatusRowID更新,我想从Applicant.AppStatusRowID,Applicant.FirstName,Applicant.Lastname,Location.LocNumber,Location.LocationName,Company.CompanyCode,AppStatus.DisplayText
的值联接将是:
Select * from Applicant A
Inner Join AppStatus ast on ast.RowID = a.AppStatusRowID
Inner Join Location l on l.RowID = a.LocationRowID
Inner Join Company c on c.RowID = l.CompanyRowID
这是要插入到审核表(字段ApplicantID,姓氏,名字,日期,时间,公司,地点数量,位置名称,StatusDisposition,用户)
的特里格呃查询是:
SET QUOTED_IDENTIFIER OFF
GO
SET ANSI_NULLS ON
GO
CREATE TRIGGER tri_UpdateAppDispo ON dbo.Test_App
For Update
AS
declare @Approwid int
Declare @triggername sysname
Set @rowCnt = @@rowcount
Set @triggername = object_name(@@procid)
If @rowCnt = 0
RETURN
If Update(appstatusrowid)
BEGIN
-----------------------------------------------------------------------------
-- insert a record to the AppDispo table, if AppstatusRowid
-- is being Updated
-----------------------------------------------------------------------------
Insert AppDispo(AppID, LastName, FirstName, [DateTime],Company,Location,LocationName,
StatusDispo,[Username])
Select d.Rowid,d.LastName, d.FirstName, getDate(),C.CompanyCode,l.locnum,l.locname, ast.Displaytext,
SUSER_SNAME()+' '+User
From deleted d with(nolock)
Inner join Test_App a with (nolock) on a.RowID = d.rowid
inner join location l with (nolock) on l.rowid = d.Locationrowid
inner join appstatus ast with (nolock) on ast.rowid = d.appstatusrowid
inner join company c with (nolock) on c.rowid = l.CompanyRowid
--Inner Join Deleted d ON a.RowID = d.RowID
--Where (a.rowid = @Approwid)
END
GO
任何想法?