Python检查代码是否有错误

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我已经被分配去编写一个名为author functions的程序。我写的一个功能在我看来是正确的，但我想知道是否有任何不同的写作方式，或者我的功能有任何错误。代码如下。谢谢！Python检查代码是否有错误

高清CLEAN_UP（S）： “””（STR） - > STR

Return a new string based on s in which all letters have been 
converted to lowercase and punctuation characters have been stripped 
from both ends. Inner punctuation is left untouched. 

>>> clean_up('Happy Birthday!!!') 
'happy birthday' 
>>> clean_up("-> It's on your left-hand side.") 
" it's on your left-hand side" 
""" 

punctuation = """!"',;:.-?)([]<>*#\n\t\r""" 
result = s.lower().strip(punctuation) 
return result

####完成以下功能

def avg_word_length(text): 
    """ (list of str) -> float 

    Precondition: text is non-empty. Each str in text ends with \n and 
    text contains at least one word. 

    Return the average length of all words in text. 

    >>> text = ['James Fennimore Cooper\n', 'Peter, Paul and Mary\n'] 
    >>> avg_word_length(text) 
    5.142857142857143 
    """ 

    # To do: Fill in this function's body to meet its specification. 

    x = '' 
    for i in range(len(text)): 
     x = x + clean_up(text[i]) 
     words = x.split() 
    for word in words: 
     average = sum(len(word) for word in words)/len(words) 
    return average

来源

2014-11-02 Ez2Earn

是什么'clean_up'？ – 2014-11-02 21:09:36

似乎有一些奇怪的事情发生在这里：[还有另一个问题，其中包含此作业的不同版本。]（http://stackoverflow.com/questions/26704277/i-have-to-find-the-average-word -长度）。 – Carsten 2014-11-02 21:12:09

哦我道歉它的程序与高清CLEAN_UP（S）开始： “””（STR） - > STR 返回基于在S中的所有字母都被转换为小写字母和标点符号都被剥夺了一个新的字符串（'生日快乐'） '生日快乐' >>> clean_up（“ - >它在你的左手边。”） “它在你的左边” “”“ punctuation =”“”！“'，;：.-？）（[] <> *＃\ n \ t \ r”“” result = s.lower（）。strip（标点符号）返回结果 – Ez2Earn 2014-11-02 21:13:18

您要加入的最后的，第一句话。每串在一起，你需要让一个空间：

def avg_word_length(text): 
    """ (list of str) -> float 

    Precondition: text is non-empty. Each str in text ends with \n and 
    text contains at least one word. 

    Return the average length of all words in text. 

    5.142857142857143 
    """ 
    cleaned = " ".join([clean_up(w) for w in text]).split() # join using a space between to separate the start and end of the strings 
    return sum(len(w) for w in cleaned)/len(cleaned)

在您的代码cooperpeter变成一个词让你的计算是关闭

for word in words:是无所事事的sum(len(word) for word in words)有用还遍历的话，当所有的串联通过循环完成，而不是每次你应该分裂：

for i in range(len(text)): 
    x += clean_up(text[i]) 
words = x.split() # outside the loop

来源

2014-11-02 21:36:22

非常感谢你我很感激！ – Ez2Earn 2014-11-02 21:59:39

现在担心，不客气。 – 2014-11-02 22:00:40

Python检查代码是否有错误

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