我在第二个tableview时总是出错。我使用storyboard创建一个简单的应用程序。我的应用第一次运行时,它会显示我创建的数据列表。如果用户点击该行,我想更改为其他页面,在其他页面上也有一个tableview。我也对数据列表进行了硬编码,但是我没有显示出来。从UITableView中选择单元格并转到另一个UITableView
我总是得到一个错误在这一部分
-(UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{
UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:@"SubSiteCellDetail"];
cell.textLabel.text = [ListDetailSubSite objectAtIndex:indexPath.row]; //this always give me the error
return cell;
}
这里是我创建的数据列表
ListDetailSubSite = [NSMutableArray arrayWithCapacity:10];
SubSite *detailSubSite = [[SubSite alloc] init];
detailSubSite.sSubSiteName = [subsite.sSubSiteName stringByAppendingString:@"1"];
[ListDetailSubSite addObject:detailSubSite];
detailSubSite = [[SubSite alloc] init];
detailSubSite.sSubSiteName = [subsite.sSubSiteName stringByAppendingString:@"2"];
[ListDetailSubSite addObject:detailSubSite];
这里是如何,我从UITableView中移动到另一个UITableView的。
-(void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{
if ([[segue identifier] isEqualToString:@"ShowSubSiteDetail"]) {
NSIndexPath *indexPath = [self.tableView indexPathForSelectedRow];
SubSite *subsetSelected = [ListSubSite objectAtIndex:indexPath.row];
[[segue destinationViewController] setSubsite:subsetSelected];
}
}
这是我的错误看起来像
2012-10-29 15:18:11.127 UniversalStoryBoard[5256:f803] -[SubSite isEqualToString:]: unrecognized selector sent to instance 0x9355340
2012-10-29 15:18:11.129 UniversalStoryBoard[5256:f803] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[SubSite isEqualToString:]: unrecognized selector sent to instance 0x9355340'
*** First throw call stack:
(0x13ce022 0x155fcd6 0x13cfcbd 0x1334ed0 0x1334cb2 0x1580ff 0x4fb1 0xb2c54 0xb33ce 0x9ecbd 0xad6f1 0x56d21 0x13cfe42 0x1d86679 0x1d90579 0x1d154f7 0x1d173f6 0x1d16ad0 0x13a299e 0x1339640 0x13054c6 0x1304d84 0x1304c9b 0x12b77d8 0x12b788a 0x18626 0x1fcd 0x1f35)
terminate called throwing an exception
这里是图:
类SubSite.h
#import <UIKit/UIKit.h>
@interface SubSite : NSObject
@property (nonatomic, copy) NSString *sSubSiteName;
@end
类SubSite.m
#import "SubSite.h"
@implementation SubSite
@synthesize sSubSiteName;
@end
任何人都可以帮我解决这个问题吗?谢谢。
嗨,谢谢你的答案..它真的很有帮助。再次感谢。 :) –
很高兴它解决了.. :) – Coder