拖动WPF用户控制

Question

创建移动用户控件

<UserControl x:Class="Restaurant.Views.Managerer.TablePanel" 
     xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" 
     xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" 
     xmlns:d="http://schemas.microsoft.com/expression/blend/2008" 
     xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" 
     xmlns:local="clr-namespace:Restaurant.Helpers.Converter" 
     mc:Ignorable="d" 
     x:Name="root" 
     MouseLeftButtonDown="root_MouseLeftButtonDown" 
     MouseLeftButtonUp="root_MouseLeftButtonUp" 
     MouseMove="root_MouseMove"  
     DataContext="{Binding RelativeSource={RelativeSource Self}}"> 
.... 

代码

Point anchorPoint; 
     Point currentPoint; 
     bool isInDrag = false; 

     private void root_MouseLeftButtonDown(object sender, MouseButtonEventArgs e) 
     { 
      var element = sender as FrameworkElement; 
      anchorPoint = e.GetPosition(null); 
      element.CaptureMouse(); 
      isInDrag = true; 
      e.Handled = true; 
     } 

     private void root_MouseMove(object sender, MouseEventArgs e) 
     { 
      if (isInDrag) 
      { 
       var element = sender as FrameworkElement; 
       currentPoint = e.GetPosition(null); 

       var transform = new TranslateTransform 
            { 
             X = (currentPoint.X - anchorPoint.X), 
             Y = (currentPoint.Y - anchorPoint.Y) 
            }; 
       this.RenderTransform = transform; 
       anchorPoint = currentPoint; 
      } 
     } 

     private void root_MouseLeftButtonUp(object sender, MouseButtonEventArgs e) 
     { 
      if (isInDrag) 
      { 
       var element = sender as FrameworkElement; 
       element.ReleaseMouseCapture(); 
       isInDrag = false; 
       e.Handled = true; 
      } 
     } 

如果改变代码

X = (currentPoint.X - anchorPoint.X), 
Y = (currentPoint.Y - anchorPoint.Y) 

到

X = (currentPoint.X), 
Y = (currentPoint.Y) 

我可以移动用户控件，但鼠标和用户控件不匹配

Answer 1

早上好。我睡觉，能想到的）））

private TranslateTransform transform = new TranslateTransform(); 
     private void root_MouseMove(object sender, MouseEventArgs e) 
     { 
      if (isInDrag) 
      { 
       var element = sender as FrameworkElement; 
       currentPoint = e.GetPosition(null); 

       transform.X += currentPoint.X - anchorPoint.X; 
       transform.Y += (currentPoint.Y - anchorPoint.Y); 
       this.RenderTransform = transform; 
       anchorPoint = currentPoint; 
      } 
     } 

Answer 2

我真的不确定你想要在你的问题中完成什么，但拇指更容易拖动动作。你可以看到一个解释和示例代码（在底部）here。

Answer 3

在@Mediator答案基于信息。我已经提出并编辑，以防止控制超出界限。

private TranslateTransform transform = new TranslateTransform(); 
    private void root_MouseMove(object sender, MouseEventArgs e) 
    { 
     if (isInDrag) 
     { 
      var element = sender as FrameworkElement; 
      currentPoint = e.GetPosition(null); 

      transform.X += currentPoint.X - anchorPoint.X; 
      transform.Y += (currentPoint.Y - anchorPoint.Y); 
      if (currentPoint.X < Application.Current.MainWindow.RenderSize.Width && currentPoint.Y < Application.Current.MainWindow.RenderSize.Height 
       && currentPoint.X > 0 && currentPoint.Y > 0) 
      { 
       this.RenderTransform = transform; 
       anchorPoint = currentPoint; 
      } 
      else 
      { 
       transform = new TranslateTransform(); 
       this.RenderTransform = transform; 
      } 
     } 
    } 

但是绑定错误是他们在VS中的输出窗口。

看起来这是WPF中的一个问题，但是微软无法解决这个问题。

欲了解更多资讯：

https://connect.microsoft.com/VisualStudio/feedback/details/1423399/system-windows-data-error-4-when-using-relativesource-findancestor-inside-a-translatetransform-inside-a-style