列出当月没有来自数据库的数据

当前查询工作完美的问题是当前月份（4月）没有数据，因此它不会将月份列为0，我如何获取它以列出月份有0个interivews？列出当月没有来自数据库的数据

QUERY

select distinct from_unixtime(interv_date,'%M %Y') AS month, count(*) as totals 
from " . TABLE_PREFIX . "interviews 
group by month 
order by interv_date desc 
limit 6

注意，interv_date列是一个划时代的时间戳（例如：1428003691）

PHP

<table class=\"highchart\" data-graph-container=\"#graphcontainer\" data-graph-type=\"column\" data-graph-legend-disabled=\"1\"> 
<caption>Interviews by Month</caption> 
<thead> 
<tr> 
<th>Month</th> 
<th>Totals</th> 
</tr> 
</thead> 
<tbody> 
<?php 
for ($i = 0; $i < $stat_logs["count"]; $i++) { 
    echo "<tr>\n"; 
    echo "<td>" . $stat_logs[$i]["month"] . "</td>\n"; 
    echo "<td>" . $stat_logs[$i]["totals"] . "</td>\n"; 
    echo "</tr>\n"; 
} 
?> 
echo "</tbody> 
echo "</table>

OUTPUT

Month   Totals 
March 2015  7 
February 2015 5 
January 2015 12 
December 2014 18 
November 2014 19 
October 2014 5

我需要它输出是这样的：

Month   Totals 
April 2015  0 
March 2015  7 
February 2015 5 
January 2015 12 
December 2014 18 
November 2014 19

拿不出，并不是每个月都会有面试，所以它不会只是当前月份（第一个月）我如何能拿到个月，没有采访任何人的帮助出现在名单上会很棒。

来源

2015-04-02 Manvaril

您可能想要一个具有Jan-Dec的'month'表，然后在查询中加入JOIN。尽管如果当前的“月份”列也包含年份，那可能会很麻烦。 – AbraCadaver 2015-04-02 18:55:20

所以你有兴趣过去6个月的数据包括当前月份？ – 2015-04-02 19:04:20

是包括当前月份，请注意interv_date列是纪元时间戳 – Manvaril 2015-04-02 19:39:23

我一直在WAAAAAYYYY上工作太久。但这是一个开始... http://sqlfiddle.com/#!9/23389/2

它工作得很好，但它有点笨重，有两个临时表。尽管没有硬编码日期！这些表应该实际上是临时表，尽管sqlfiddle不适用于临时表，所以我使它们成为真正的表。

-- Get a table with the months of interest in it 
SET @RightNow = curdate(); 
create table LastSixMonths (dateVal datetime); 
Insert into LastSixMonths values(@RightNow); 
Insert into LastSixMonths values(@RightNow - INTERVAL 1 MONTH); 
Insert into LastSixMonths values(@RightNow - INTERVAL 2 MONTH); 
Insert into LastSixMonths values(@RightNow - INTERVAL 3 MONTH); 
Insert into LastSixMonths values(@RightNow - INTERVAL 4 MONTH); 
Insert into LastSixMonths values(@RightNow - INTERVAL 5 MONTH); 

-- Summarize the recent interviews 
create table Totals (monthAndYear varchar (20), interviews int); 
Insert into Totals 
select distinct from_unixtime(intv.interv_date,'%M %Y') as monthAndYear, 
       count(*) 
from interviews intv 
group by from_unixtime(intv.interv_date,'%M %Y') 
order by interv_date desc 
limit 6 

-- Do a left join on recent months and summarized interviews 
select date_format(six.dateval, '%M %Y'), 
    IF (interviews IS NULL, 0, Interviews) as totalInterviews 
from LastSixMonths six 
left join Totals tot 
    on date_format(six.dateval, '%M %Y') = tot.monthAndYear 
order by six.dateval desc 
limit 6;

来源

2015-04-03 01:49:17 CindyH

列出当月没有来自数据库的数据

回答

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