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我一直在尝试调试我的代码,因为我知道内核中出现了问题,我一直试图弄清楚具体是什么。如果我尝试步入内核似乎在内核函数完全步骤,并将最终导致对戒烟的错误:CUDA-GDB在内核中崩溃
Single stepping until exit from function dyld_stub_cudaSetupArgument,
which has no line number information.
[Launch of CUDA Kernel 0 (incrementArrayOnDevice<<<(3,1,1),(4,1,1)>>>) on
Device 0]
[Termination of CUDA Kernel 0 (incrementArrayOnDevice<<<(3,1,1),
(4,1,1)>>>) on Device 0]
[Launch of CUDA Kernel 1 (fillinBoth<<<(40,1,1),(1,1,1)>>>) on Device 0]
[Termination of CUDA Kernel 1 (fillinBoth<<<(40,1,1),(1,1,1)>>>) on Device 0]
add (below=0x124400, newtip=0x124430, newfork=0x125ac0) at test.cu:1223
如果我尝试在内核打破我的整个计算机崩溃,我有重新启动它。
我认为我调用内核的方式肯定有问题,但我不知道是什么。
的代码比较长,所以我只包括它的一个摘录:
__global__ void fillinOne(seqptr qset, long max) {
int i, j;
aas aa;
int idx = blockIdx.x;
__shared__ long qs[3];
if(idx < max)
{
memcpy(qs, qset[idx], sizeof(long[3]));
for (i = 0; i <= 1; i++)
{
for (aa = ala; (long)aa <= (long)stop; aa = (aas)((long)aa + 1))
{
if (((1L << ((long)aa)) & qs[i]) != 0)
{
for (j = i + 1; j <= 2; j++)
qs[j] |= cudaTranslate[(long)aa - (long)ala][j - i];
}
}
}
}
}
//Kernel for left!= NULL and rt != NULL
void fillin(node *p, node *left, node *rt)
{
cudaError_t err = cudaGetLastError();
size_t stepsize = chars * sizeof(long);
size_t sitesize = chars * sizeof(sitearray);
//int i, j;
if (left == NULL)
{
//copy rt->numsteps into p->numsteps--doesn't actually require CUDA, because no computation to do
memcpy(p->numsteps, rt->numsteps, stepsize);
checkCUDAError("memcpy");
//allocate siteset (array of sitearrays) on device
seqptr qsites; //as in array of qs's
cudaMalloc((void **) &qsites, sitesize);
checkCUDAError("malloc");
//copy rt->siteset into device array (equivalent to memcpy(qs, rs) but for whole array)
cudaMemcpy(qsites, rt->siteset, sitesize, cudaMemcpyHostToDevice);
checkCUDAError("memcpy");
//do loop in device
int block_size = 1; //each site operated on independently
int n_blocks = chars;
fillinOne <<< n_blocks, block_size>>> (qsites, chars);
cudaThreadSynchronize();
//put qset in p->siteset--equivalent to memcpy(p->siteset[m], qs)
cudaMemcpy(p->siteset, qsites, sitesize, cudaMemcpyDeviceToHost);
checkCUDAError("memcpy");
//Cleanup
cudaFree(qsites);
}
如果任何人有任何想法都请resond!提前致谢!
感谢您的回应!这是有道理的,但你怎么在命令行模式中使用它?我认为这就是我一直在做的事情。我一直从命令行运行cuda-gdb a.out。我应该怎么做呢? – Izri
您可能只是在桌面环境中打开一个终端。如果按下ctrl-alt-f1,则在桌面环境之外进入命令行(我认为它被称为控制台)。为了回报你,我只想做ctrl-alt-f7。 – jmsu