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这里是我的代码阅读数学函数问题
import math
try:
valor = float(input("Give a real number "))
print("Your value given is: ", value)
except ValueError:
print("You gave a value not interpretable as a real onel!!")
而当我输入为sqrt(2)
,我得到这个错误,任何人都知道这是为什么?
%run "c:\users\aar15\appdata\local\temp\tmpvzauzz.py"
Give a real number sqrt(2)
---------------------------------------------------------------------------
NameError Traceback (most recent call last)
c:\users\aar15\appdata\local\temp\tmpvzauzz.py in <module>()
1 import math
2 try:
----> 3 valor = float(input("Give a real number "))
4 print("Your value given is: ", value)
5 except ValueError:
C:\Users\aar15\AppData\Local\Enthought\Canopy\App\appdata\canopy-1.6.1.3253.win-x86_64\lib\site-packages\IPython\kernel\zmq\ipkernel.pyc in <lambda>(prompt)
C:\Users\aar15\AppData\Local\Enthought\Canopy\App\appdata\canopy-1.6.1.3253.win-x86_64\lib\site-packages\IPython\kernel\zmq\ipkernel.pyc in <module>()
NameError: name 'sqrt' is not defined
也许开方(2)被解释为需要的eval一个字符串()在铸造浮动之前?或者你需要math.sqrt(2)。测试valor = float(sqrt(2)))是否给出错误可能会很好。 –