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我在PostgreSQL的下表：使用JPA工具生成的这些Java实体是否正确？
CREATE TABLE public.company_subscripcion (
id_suscription int4 NOT NULL,
status char(1) NOT NULL,
id_company int4 NOT NULL,
PRIMARY KEY(id_suscription,id_company)
)
GO
ALTER TABLE public.company_subscripcion
ADD CONSTRAINT company_subscripcion_id_suscription_fkey
FOREIGN KEY(id_suscription)
REFERENCES public.subscription(id_suscription)
ON DELETE NO ACTION
ON UPDATE NO ACTION
GO
ALTER TABLE public.company_subscripcion
ADD CONSTRAINT company_subscripcion_id_company_fkey
FOREIGN KEY(id_company)
REFERENCES public.company(id_company)
ON DELETE NO ACTION
ON UPDATE NO ACTION
GO
CREATE TABLE public.company (
id_company int4 NOT NULL,
id_corporation int4 NULL,
tin varchar(20) NOT NULL,
short_name varchar(20) NOT NULL,
name varchar(100) NOT NULL,
commercial_name varchar(100) NOT NULL,
address varchar(200) NOT NULL,
phone_number varchar(20) NULL,
logo_url varchar(500) NULL,
created_by int4 NOT NULL,
created timestamp NOT NULL,
updated_by int4 NULL,
last_update timestamp NULL,
s3_bucket varchar(20) NULL,
s3_access varchar(20) NULL,
s3_secret varchar(20) NULL,
sunat_username varchar(30) NULL,
sunat_password varchar(64) NULL,
others text NULL,
PRIMARY KEY(id_company)
)
CREATE TABLE public.subscription (
id_suscription int4 NOT NULL,
automatic_renewal char(1) NOT NULL,
amount numeric(10,2) NOT NULL,
status char(1) NOT NULL,
start_date date NULL,
expiration_date date NULL,
id_user int4 NULL,
id_plan int4 NOT NULL,
created_by int4 NOT NULL,
created timestamp NOT NULL,
updated_by int4 NULL,
last_update timestamp NULL,
PRIMARY KEY(id_suscription)
)
JPA的工具，我产生这些实体：
CompanySubscripcion.java
@Entity
@Table(name="company_subscripcion")
@NamedQuery(name="CompanySubscripcion.findAll", query="SELECT c FROM CompanySubscripcion c")
public class CompanySubscripcion implements Serializable {
private static final long serialVersionUID = 1L;
@EmbeddedId
private CompanySubscripcionPK id;
private String status;
private Company company;
private Subscription subscription;
public CompanySubscripcion() {
}
public CompanySubscripcionPK getId() {
return this.id;
}
public void setId(CompanySubscripcionPK id) {
this.id = id;
}
@Column(nullable=false, length=1)
public String getStatus() {
return this.status;
}
public void setStatus(String status) {
this.status = status;
}
//uni-directional many-to-one association to Company
@ManyToOne
@JoinColumn(name="id_company", nullable=false, insertable=false, updatable=false)
public Company getCompany() {
return this.company;
}
public void setCompany(Company company) {
this.company = company;
}
//uni-directional many-to-one association to Subscription
@ManyToOne
@JoinColumn(name="id_suscription", nullable=false, insertable=false, updatable=false)
public Subscription getSubscription() {
return this.subscription;
}
public void setSubscription(Subscription subscription) {
this.subscription = subscription;
}
}
CompanySubscripcionPK.java
@Embeddable
public class CompanySubscripcionPK implements Serializable {
//default serial version id, required for serializable classes.
private static final long serialVersionUID = 1L;
private Integer idSuscription;
private Integer idCompany;
public CompanySubscripcionPK() {
}
@Column(name="id_suscription", insertable=false, updatable=false, unique=true, nullable=false)
public Integer getIdSuscription() {
return this.idSuscription;
}
public void setIdSuscription(Integer idSuscription) {
this.idSuscription = idSuscription;
}
@Column(name="id_company", insertable=false, updatable=false, unique=true, nullable=false)
public Integer getIdCompany() {
return this.idCompany;
}
public void setIdCompany(Integer idCompany) {
this.idCompany = idCompany;
}
public boolean equals(Object other) {
if (this == other) {
return true;
}
if (!(other instanceof CompanySubscripcionPK)) {
return false;
}
CompanySubscripcionPK castOther = (CompanySubscripcionPK)other;
return
this.idSuscription.equals(castOther.idSuscription)
&& this.idCompany.equals(castOther.idCompany);
}
public int hashCode() {
final int prime = 31;
int hash = 17;
hash = hash * prime + this.idSuscription.hashCode();
hash = hash * prime + this.idCompany.hashCode();
return hash;
}
}
我有这样的疑问，因为当我消耗ReadAllQuery方法（我使用的EclipseLink）阅读company_subscripcion表的数据，我得到这个错误：
[EL Finest]: query: 2017-05-05 16:29:52.328--UnitOfWork(1108818591)--Thread(Thread[http-nio-8081-exec-8,5,main])--Execute query ReadAllQuery(referenceClass=CompanySubscripcion sql="SELECT STATUS, IDCOMPANY, IDSUSCRIPTION, COMPANY_id_company, SUBSCRIPTION_id_suscription FROM company_subscripcion")
[EL Finest]: connection: 2017-05-05 16:29:52.328--ServerSession(2070565177)--Connection(641062437)--Thread(Thread[http-nio-8081-exec-8,5,main])--Connection acquired from connection pool [default].
[EL Fine]: sql: 2017-05-05 16:29:52.328--ServerSession(2070565177)--Connection(641062437)--Thread(Thread[http-nio-8081-exec-8,5,main])--SELECT STATUS, IDCOMPANY, IDSUSCRIPTION, COMPANY_id_company, SUBSCRIPTION_id_suscription FROM company_subscripcion
[EL Fine]: sql: 2017-05-05 16:29:52.331--ServerSession(2070565177)--Thread(Thread[http-nio-8081-exec-8,5,main])--SELECT 1
[EL Finest]: connection: 2017-05-05 16:29:52.333--ServerSession(2070565177)--Connection(641062437)--Thread(Thread[http-nio-8081-exec-8,5,main])--Connection released to connection pool [default].
[EL Warning]: 2017-05-05 16:29:52.333--UnitOfWork(1108818591)--Thread(Thread[http-nio-8081-exec-8,5,main])--Local Exception Stack:
Exception [EclipseLink-4002] (Eclipse Persistence Services - 2.5.0.v20130507-3faac2b): org.eclipse.persistence.exceptions.DatabaseException
Internal Exception: org.postgresql.util.PSQLException: ERROR: no existe la columna «idcompany»
Hint: Perhaps you meant to reference the column "company_subscripcion.id_company".
Position: 16
Error Code: 0
Call: SELECT STATUS, IDCOMPANY, IDSUSCRIPTION, COMPANY_id_company, SUBSCRIPTION_id_suscription FROM company_subscripcion
Query: ReadAllQuery(referenceClass=CompanySubscripcion sql="SELECT STATUS, IDCOMPANY, IDSUSCRIPTION, COMPANY_id_company, SUBSCRIPTION_id_suscription FROM company_subscripcion")
at org.eclipse.persistence.exceptions.DatabaseException.sqlException(DatabaseException.java:340)
at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.basicExecuteCall(DatabaseAccessor.java:679)
at org.eclipse.persistence.internal.databaseaccess.DatabaseAccessor.executeCall(DatabaseAccessor.java:558)
at org.eclipse.persistence.internal.sessions.AbstractSession.basicExecuteCall(AbstractSession.java:1995)
at org.eclipse.persistence.sessions.server.ServerSession.executeCall(ServerSession.java:570)
感谢您的帮助我:)
更新1
我已经生成实体了，现在他们的工作。这个新的权利与以前不同：
@Entity
@Table(name="company_subscripcion")
@NamedQuery(name="CompanySubscripcion.findAll", query="SELECT c FROM CompanySubscripcion c")
public class CompanySubscripcion implements Serializable {
private static final long serialVersionUID = 1L;
@EmbeddedId
private CompanySubscripcionPK id;
private String status;
//bi-directional many-to-one association to Company
@ManyToOne
@JoinColumn(name="id_company")
private Company company;
//bi-directional many-to-one association to Subscription
@ManyToOne
@JoinColumn(name="id_suscription")
private Subscription subscription;
public CompanySubscripcion() {
}
public CompanySubscripcionPK getId() {
return this.id;
}
public void setId(CompanySubscripcionPK id) {
this.id = id;
}
public String getStatus() {
return this.status;
}
public void setStatus(String status) {
this.status = status;
}
public Company getCompany() {
return this.company;
}
public void setCompany(Company company) {
this.company = company;
}
public Subscription getSubscription() {
return this.subscription;
}
public void setSubscription(Subscription subscription) {
this.subscription = subscription;
}
}
@Embeddable
public class CompanySubscripcionPK implements Serializable {
//default serial version id, required for serializable classes.
private static final long serialVersionUID = 1L;
@Column(name="id_suscription", insertable=false, updatable=false)
private Integer idSuscription;
@Column(name="id_company", insertable=false, updatable=false)
private Integer idCompany;
public CompanySubscripcionPK() {
}
public Integer getIdSuscription() {
return this.idSuscription;
}
public void setIdSuscription(Integer idSuscription) {
this.idSuscription = idSuscription;
}
public Integer getIdCompany() {
return this.idCompany;
}
public void setIdCompany(Integer idCompany) {
this.idCompany = idCompany;
}
public boolean equals(Object other) {
if (this == other) {
return true;
}
if (!(other instanceof CompanySubscripcionPK)) {
return false;
}
CompanySubscripcionPK castOther = (CompanySubscripcionPK)other;
return
this.idSuscription.equals(castOther.idSuscription)
&& this.idCompany.equals(castOther.idCompany);
}
public int hashCode() {
final int prime = 31;
int hash = 17;
hash = hash * prime + this.idSuscription.hashCode();
hash = hash * prime + this.idCompany.hashCode();
return hash;
}
}
我的问题已解决。谢谢。
但是列id_company确实存在......我会知道是否使用JPA工具自动生成的实体是正确的 –
自动生成的工具应该可以工作。你可以尝试删除“私人公司公司”吗？并且它是getter和setter方法来查看这是否是问题？ –
我已经注意到某些东西有线，查询产生的是这一个：SELECT STATUS，IDCOMPANY，IDSUSCRIPTION，COMPANY_ID_company，SUBSCRIPTION_id_suscription FROM company_subscripcion –