python排序字​​典问题

Question

如果我有一个CSV文件，每行有一个字典值（列为[“位置”]，[“MovieDate”]，[“Formatted_Address”]，[“Lat”]， “Lng”]），如果我想按Location进行分组，并且在共享相同Location值的所有MovieDate值上进行分组，则需要使用OrderDict。

前的数据：

Location,MovieDate,Formatted_Address,Lat,Lng 
    "Edgebrook Park, Chicago ",Jun-7 A League of Their Own,"Edgebrook Park, 6525 North Hiawatha Avenue, Chicago, IL 60646, USA",41.9998876,-87.7627672 
    "Edgebrook Park, Chicago ","Jun-9 It's a Mad, Mad, Mad, Mad World","Edgebrook Park, 6525 North Hiawatha Avenue, Chicago, IL 60646, USA",41.9998876,-87.7627672 

对于具有相同的位置（^如本例）中的每一行，我想做出这样的输出，以便有没有重复的位置。

"Edgebrook Park, Chicago ","Jun-7 A League of Their Own Jun-9 It's a Mad, Mad, Mad, Mad World","Edgebrook Park, 6525 North Hiawatha Avenue, Chicago, IL 60646, USA",41.9998876,-87.7627672 

我的代码使用ordereddict来做这件事有什么问题吗？

from collections import OrderedDict 

od = OrderedDict() 
import csv 
with open("MovieDictFormatted.csv") as f,open("MoviesCombined.csv" ,"w") as out: 
    r = csv.reader(f) 
    wr = csv.writer(out) 
    header = next(r) 
    for row in r: 
     loc,rest = row[0], row[1] 
     od.setdefault(loc, []).append(rest) 
    wr.writerow(header) 
    for loc,vals in od.items(): 
     wr.writerow([loc]+vals) 

我最终得到的是这样的：

['Edgebrook Park, Chicago ', 'Jun-7 A League of Their Own'] 
['Gage Park, Chicago ', "Jun-9 It's a Mad, Mad, Mad, Mad World"] 
['Jefferson Memorial Park, Chicago ', 'Jun-12 Monsters University ', 'Jul-11 Frozen ', 'Aug-8 The Blues Brothers '] 
['Commercial Club Playground, Chicago ', 'Jun-12 Despicable Me 2'] 

的问题是，我没有得到其他列在这种情况下展现出来，我会怎么做才好？我也宁愿让MovieDate值只是一个长字符串，如下：的 'Jun-12 Monsters University Jul-11 Frozen Aug-8 The Blues Brothers ' 代替：

'Jun-12 Monsters University ', 'Jul-11 Frozen ', 'Aug-8 The Blues Brothers ' 

感谢球员，欣赏它。我是一个python noob。

更改row[0], row[1]到row[0], row[1:]遗憾的是不给我我想要的。我只希望被添加在第二列（MovieDate）的值，而不是复制所有其他列，例如：

['Jefferson Memorial Park, Chicago ', ['Jun-12 Monsters University ', 'Jefferson Memorial Park, 4822 North Long Avenue, Chicago, IL 60630, USA', '41.76083920000001', '-87.6294353'], ['Jul-11 Frozen ', 'Jefferson Memorial Park, 4822 North Long Avenue, Chicago, IL 60630, USA', '41.76083920000001', '-87.6294353'], ['Aug-8 The Blues Brothers ', 'Jefferson Memorial Park, 4822 North Long Avenue, Chicago, IL 60630, USA', '41.76083920000001', '-87.6294353']] 

Answer 1

你只需要一对夫妇的变化，你需要加入lat和长，去除重复数据删除纬度和渴望，我们还需要使用的关键：

with open("data.csv") as f,open("new.csv" ,"w") as out: 
    r = csv.reader(f) 
    wr= csv.writer(out) 
    header = next(r) 
    for row in r: 
     od.setdefault((row[0], row[-2], row[-1]), []).append(" ".join(row[1:-2])) 
    wr.writerow(header) 
    for loc,vals in od.items(): 
     wr.writerow([loc[0]] + vals+list(loc[1:])) 

输出：

Location,MovieDate,Formatted_Address,Lat,Lng 
"Edgebrook Park, Chicago ","Jun-7 A League of Their Own Edgebrook Park, 6525 North Hiawatha Avenue, Chicago, IL 60646, USA","Jun-9 It's a Mad, Mad, Mad, Mad World Edgebrook Park, 6525 North Hiawatha Avenue, Chicago, IL 60646, USA",41.9998876,-87.7627672 

A League of Their Own首先是因为它是疯狂的，疯狂前行， row[1:-2]得到的一切吧拉特，L ong和location，我们将纬度和长度存储在我们的关键元组中，以避免在每行末尾重复写入。

使用的名称和拆包可能更容易一点遵循：

with open("data.csv") as f, open("new.csv", "w") as out: 
    r = csv.reader(f) 
    wr = csv.writer(out) 
    header = next(r) 
    for row in r: 
     loc, mov, form, lat, long = row 
     od.setdefault((loc, lat, long), []).append("{} {}".format(mov, form)) 
    wr.writerow(header) 
    for loc, vals in od.items(): 
     wr.writerow([loc[0]] + vals + list(loc[1:])) 

使用CSV。Dictwriter保持五列：

od = OrderedDict() 
import csv 

with open("data.csv") as f, open("new.csv", "w") as out: 
    r = csv.DictReader(f,fieldnames=['Location', 'MovieDate', 'Formatted_Address', 'Lat', 'Lng']) 
    wr = csv.DictWriter(out, fieldnames=r.fieldnames) 
    for row in r: 
     od.setdefault(row["Location"], dict(Location=row["Location"], Lat=row["Lat"], Lng=row["Lng"], 
             MovieDate=[], Formatted_Address=row["Formatted_Address"])) 

     od[row["Location"]]["MovieDate"].append(row["MovieDate"]) 
    for loc, vals in od.items(): 
     od[loc]["MovieDate"]= ", ".join(od[loc]["MovieDate"]) 
     wr.writerow(vals) 

＃ 输出：

"Edgebrook Park, Chicago ","Jun-7 A League of Their Own, Jun-9 It's a Mad, Mad, Mad, Mad World","Edgebrook Park, 6525 North Hiawatha Avenue, Chicago, IL 60646, USA",41.9998876,-87.7627672 

所以五柱保持完好，我们加入了"MovieDate"成单串和Formatted_Address=form始终是唯一的，所以我们并不需要更新。

事实证明，我们需要做的只是连接MovieDate's，并删除位置，Lat，Lng和'Formatted_Address'的重复条目。

Answer 2

让我们尝试改变

od.setdefault(loc, []).append(rest) 

要

od[loc] = ' '.join([od.get(loc, ''), ' 'join(rest)]) 

再拥有这个是：

wr.writerow([loc]+vals) 

Answer 3

假设位置是该行的第一个项目：

dict = {} 
for line in f: 
    if line[0] not in dict: 
     dict[line[0]] = [] 
    dict[line[0]].append(line[1:]) 

而对于每一个位置，你有行

for key, value in dict.iteritems(): 
    out.write(key + value)