解码JSON用方括号

Question

我试图此JSON解码，但没有运气，这些方括号是让我困惑 任何帮助，将不胜感激，这是我的JSON

[{"location":[{"building":["Default Building"],"name":"Default Location"}],"name":"Default Organization"}] 

谢谢

Answer 1

试试这个：

var_export(json_decode('[{"location":[{"building":["Default Building"],"name":"Default Location"}],"name":"Default Organization"}]') ); 

json_decode返回数组或object。你可以用var_export不echo

打印，你可以访问到的值：

$items = json_decode('[{"location":[{"building":["Default Building"],"name":"Default Location"}],"name":"Default Organization"}]'); 

foreach($items as $each){ 
    echo $each->location[0]->building[0]; 
    echo '<hr />'; 
    echo $each->location[0]->name; 
    echo '<hr />'; 
    echo $each->name; // default organization 
} 

Answer 2

好像它是一个有效的JSON。

$my_json = '[{"location":[{"building":["Default Building"],"name":"Default Location"}],"name":"Default Organization"}]'; 
$my_data = json_decode($my_json); 
print_r($my_data); 

//输出

Array 
(
    [0] => stdClass Object 
     (
      [location] => Array 
       (
        [0] => stdClass Object 
         (
          [building] => Array 
           (
            [0] => Default Building 
           ) 

          [name] => Default Location 
         ) 

       ) 

      [name] => Default Organization 
     ) 

) 

Answer 3

您的JSON是有效的，可能是你所面临的问题，同时访问数组内的对象。

print_r总是理解数组结构的好朋友。试试这个

$json = '[{"location":[{"building":["Default Building"],"name":"Default Location"}],"name":"Default Organization"}]'; 
$decoded = json_decode($json); 

echo '<pre>'; 
print_r($decoded); 

$location = $decoded[0]->location; 
$building = $location[0]->building[0]; 
$name = $location[0]->name; 

对象在场所0只返回的第一个项目，如果你的阵列有多个值，则使用的foreach