我试图用foreach函数但得到错误。这里是我的代码:Foreach和DISTINCT与函数PHP mysql
function student_image_list(){
global $host, $dbname, $user, $pass;
$DBH = new PDO("mysql:host=$host;dbname=$dbname", $user, $pass);
$STH = $DBH->query("SELECT DISTINCT folder_name from school_students_images");
$STH->setFetchMode(PDO::FETCH_ASSOC);
$row = $STH->fetch();
return $row;
}
我想从表school_students_images
打印所有独特的文件夹名称,我想这样的:
$folder_name1 = student_image_list();
foreach($folder_name1['folder_name'] as $folder_name)
{
echo ' <div class="mws-panel grid_2">
<div class="mws-panel-header">
<span>'.$folder_name.'</span>
</div>
</div>';
}
错误 警告:的foreach提供了无效的参数()在这一行上线41 错误student_image_list_raw.php
foreach($folder_name1['folder_name'] as $folder_name)
请帮助。
你忘了,包括错误文本和行号。 – Quassnoi
错误补充请帮忙 – Harinder