多个查询

Question

（也贴here）

所以我有两个表，一个是invalid表，另一个是valid表。

valid表：

id 
status 
date 

invalid表：

id 
status 
date 

我不得不产生这种输出报告：在2公共字段：

date  on-time late total valid invalid1 invalid2 total rate 
--------- ------- ---- ----- ----- -------- -------- ----- ---- 
9/10/2011 4  10 14  3  3   3   6 

• date Ť ABLES，场小组通过，有多少条记录在那一天有
• on-time：在有效的表中的所有ID的数量
• late：对无效的表
• total所有记录（ID）数：对时间总计和
末
• valid：与“有效”状态的有效表ID的数量
• invalid1：与“invalid1”状态
• invalid2无效的表ID的计数：计数ID与 “invalid2” 状态
• total无效表：总有效invalid1的，invalid2
• rate：平均总量

这是一个与不同的表基本上多个查询。我怎样才能实现它？

Answer 1

成才这样吗？

SELECT 
    *, 
    (result.total + result._total)/2 AS rate 
FROM (
    SELECT 
     date, 
     SUM(CASE WHEN data.valid = 1 THEN 1 ELSE 0 END) AS ontime, 
     SUM(CASE WHEN data.valid = 0 THEN 1 ELSE 0 END) AS late, 
     COUNT(*) AS total, 
     SUM(CASE WHEN data.valid = 1 AND data.status = 'valid' THEN 1 ELSE 0 END) AS valid, 
     SUM(CASE WHEN data.valid = 0 AND data.status = 'invalid1' THEN 1 ELSE 0 END) AS invalid1, 
     SUM(CASE WHEN data.valid = 0 AND data.status = 'invalid2' THEN 1 ELSE 0 END) AS invalid2, 
     SUM(CASE WHEN data.status IN ('valid', 'invalid', 'invalid2') THEN 1 ELSE 0 END) AS _total 

    FROM (
     SELECT 
      date, 
      status, 
      valid = 1 
     FROM 
      Valid 
     UNION ALL 
     SELECT 
      date, 
      status, 
      valid = 0 
     FROM 
      InValid) AS data 
    GROUP BY 
     date) AS result 

Answer 2

SELECT date, ontime, late, ontime+late total, valid, invalid1, invalid2, valid+invalid1+invalid2 total 
FROM 
(SELECT date, 
     COUNT(*) late, 
     COUNT(IIF(status = 'invalid1', 1, NULL)) invalid1, 
     COUNT(IIF(status = 'invalid2', 1, NULL)) invalid2, 
FROM invalid 
GROUP BY date 
) JOIN (
SELECT date, 
     COUNT(*) ontime, 
     COUNT(IIF(status = 'valud', 1, NULL)) valid, 
FROM valid 
GROUP BY date 
) USING (date) 

Answer 3

首先，似乎你持有恰好在2台相同的信息 - 我建议合并这些表一起，并添加一个名为valid一个额外的布尔列，以保存有关记录的有效性信息。

你的存在的数据库结构的查询可能是这个样子：

SELECT unioned.* FROM (
    (SELECT v.date AS date, v.status AS status, v.id AS id, COUNT(id) AS valid, 0 AS invalid1, 0 AS invalid2 FROM valid v GROUP BY v.date) 
    UNION 
    (SELECT i1.date AS date, i1.status AS status, i1.id AS id, 0 AS valid, COUNT(i1.id) AS invalid1, 0 AS invalid2 FROM invalid1 i1 GROUP BY i1.date) 
    UNION 
    (SELECT i2.date AS date, i2.status AS status, i2.id AS id, 0 AS valid, 0 AS invalid1, COUNT(i.id) AS invalid2 FROM invalid1 i1 GROUP BY i1.date) 

) AS unioned GROUP BY unioned.date