如何设置电子邮件权限时登录Facebook（安卓）

Question

我正在一个应用程序，我想使用Facebook登录。但我只想在开始时要求获得“电子邮件”权限，然后在用户想要发布时再发布“publish_actions”。 我按照Facebook网站中的开发人员教程，但它不像我预期的那样工作。我的问题是第一次登录。这是我LoggingFragment的代码：

import java.util.Arrays; 
import java.util.List; 

import android.content.Intent; 
import android.os.Bundle; 
import android.os.Message; 
import android.support.v4.app.Fragment; 
import android.util.Log; 
import android.view.LayoutInflater; 
import android.view.View; 
import android.view.ViewGroup; 
import android.widget.LinearLayout; 
import android.widget.RelativeLayout; 

import com.facebook.Session; 
import com.facebook.Session.OpenRequest; 
import com.facebook.SessionState; 
import com.facebook.UiLifecycleHelper; 
import com.facebook.widget.LoginButton; 


public class LoginFragment2 extends Fragment { 

private static final List<String> public_permissions = Arrays.asList("publish_actions"); 
private static final List<String> basic_permissions = Arrays.asList("email"); 
private boolean pendingPublishReauthorization = false; 
private static final String TAG = "LoginFragment2"; 
private UiLifecycleHelper uiHelper; 
App app; 
Boolean mLogged = false; 

@Override 
public void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 
    Log.d("LOGIN", "LoginFragment onCreate "); 
    uiHelper = new UiLifecycleHelper(getActivity(), callback); 
    uiHelper.onCreate(savedInstanceState); 
    app = ((App) getActivity().getApplication()); 
    mLogged = app.isLoggedIn(); 
    app.addHandler(mHandler); 
} 

@Override 
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) { 
    View view = inflater.inflate(R.layout.activity_login_activity2, container, false); 

    LoginButton authButton = (LoginButton) view.findViewById(R.id.authButton); 
    authButton.setFragment(this); 
    authButton.setReadPermissions(basic_permissions); 

    LinearLayout login_screen = (LinearLayout) view.findViewById(R.id.login_screen); 
    RelativeLayout loading_screen = (RelativeLayout) view.findViewById(R.id.loading_screen); 

    if (app.isLoggedIn()) { 
     login_screen.setVisibility(View.GONE); 
     loading_screen.setVisibility(View.VISIBLE); 
    } else { 
     login_screen.setVisibility(View.VISIBLE); 
     loading_screen.setVisibility(View.GONE); 
    } 

    return view; 
} 

@Override 
public void onResume() { 
    super.onResume(); 
    Log.d("LOGIN", "LoginFragment onResume "); 

    if (mLogged) { 
     OpenRequest openrequest = new OpenRequest(this).setPermissions(basic_permissions); 
     // For scenarios where the main activity is launched and user 
     // session is not null, the session state change notification 
     // may not be triggered. Trigger it if it's open/closed. 
     // Session session = Session.getActiveSession(); 
     Session session = new Session(getActivity()); 
     session.openForRead(openrequest); 
     if (session != null && (session.isOpened() || session.isClosed())) { 
      onSessionStateChange(session, session.getState(), null); 
     } 

     if (session != null) { 
      // OpenRequest openrequest = new 
      // OpenRequest(this).setPermissions(basic_permissions); 
      // session.openForRead(openrequest); 
      Log.d("LOGIN", "Session!=null "); 
      Log.d("LOGIN", "Session state: " + session.getState()); 
      Log.d("LOGIN", "Session spermissions: " + session.getPermissions()); 
     } 
     // } else{ 
    } 
    Session session = Session.getActiveSession(); 
    if (session != null && 
      (session.isOpened() || session.isClosed())) { 
     onSessionStateChange(session, session.getState(), null); 
    } 

    uiHelper.onResume(); 
    // } 

} 

@Override 
public void onActivityResult(int requestCode, int resultCode, Intent data) { 
    super.onActivityResult(requestCode, resultCode, data); 
    uiHelper.onActivityResult(requestCode, resultCode, data); 
} 

@Override 
public void onPause() { 
    super.onPause(); 
    uiHelper.onPause(); 
} 

@Override 
public void onDestroy() { 
    super.onDestroy(); 
    uiHelper.onDestroy(); 
} 

@Override 
public void onSaveInstanceState(Bundle outState) { 
    super.onSaveInstanceState(outState); 
    uiHelper.onSaveInstanceState(outState); 
} 

private void onSessionStateChange(Session session, SessionState state, Exception exception) { 
    if (state.isOpened()) { 

     app.LoginApp("facebook:" + session.getAccessToken()); 
     app.setSessionFacebook(session); 
    } else if (state.isClosed()) { 
     Log.d("LOGIN", "Logged out..."); 
    } 
} 

private Session.StatusCallback callback = new Session.StatusCallback() { 
    @Override 
    public void call(Session session, SessionState state, Exception exception) { 
     onSessionStateChange(session, state, exception); 
    } 
}; 

private MsgHandler mHandler = new MsgHandler(this); 

private MsgHandler msgHandler = new MsgHandler(this); 

private static class MsgHandler extends WeakReferenceHandler<LoginFragment2> { 
    public MsgHandler(LoginFragment2 fragment) { 
     super(fragment); 
    } 

    @Override 
    public void handleMessage(LoginFragment2 mfragment, Message msg) { 

     switch (msg.what) { 
     /**************/ 

     } 
    } 
} 

的问题是，你会本身，我尝试设置权限为“邮箱”的onCreateView方法，将其设置为authButton。但是，当我登录时，会话返回拥有更多权限，包括“发布”权限。 我不知道我做错了什么，因为我只是按照Facebook的说明，并按照他们的说法打电话给它的SDK。

有没有人有这个问题？任何想法发生了什么？在此先感谢

也许我应该说，要求用户确认权限的对话框显示正确的，所以“公共信息，朋友列表和电子邮件”，这是基本信息和电子邮件，我想要的。然后，onSessionChange的回调函数返回一个具有更多权限的会话

Answer 1

如果您已经在过去授予了应用发布权限，那么这些权限将转移到下一个会话（无论您使用哪种设备或网站，继续），而不管该应用程序当前要求的初始权限。

基本上，您获得了要求的权限的超集，因为您已经在过去为应用提供了更多权限。