如何知道什么值从我的Activity发送到MySql服务器在android

我使用Volley向MySQL发送数据。我不知道为什么我的数据没有插入到MySQL中，我想看到从Activity发送到MySQL服务器的数据。波纹管是我的代码如何知道什么值从我的Activity发送到MySql服务器在android

private void SendDatatoserver(final String name,final String bname,final String location,final String phone, 
       final String website,final String disc,final String ownerphone,final String gname,final String latlong, final String spinner) 
    { 

     String tag_string_req = "req_vend_reg"; 

     pDialog.setMessage("Registering Please Wait ..."); 
     showDialog(); 

     StringRequest strReq = new StringRequest(Request.Method.POST, 
       AppURLs.Vend_URL, new Response.Listener<String>() { 

      @Override 
      public void onResponse(String response) { 
       hideDialog(); 
       //Log.d(TAG, response.toString()); 

       try { 
        JSONObject jObj = new JSONObject(response); 
        boolean error = jObj.getBoolean("error"); 

        if (!error) { 
         Intent intent = new Intent(AddNewBusiness.this, SuccessBsub.class); 
         startActivity(intent); 
         finish(); 
        } else { 
         String errorMsg = jObj.getString("error_msg"); 
         Toast.makeText(getApplicationContext(), 
           errorMsg, Toast.LENGTH_LONG).show(); 
        } 
       } catch (JSONException e) { 
        e.printStackTrace(); 
       } 

      } 
     },new Response.ErrorListener() { 

      @Override 
      public void onErrorResponse(VolleyError error) { 
       Toast.makeText(getApplicationContext(), 
         error.getMessage(), Toast.LENGTH_LONG).show(); 
       hideDialog(); 
      } 
     }){ 

      @Override 
      protected Map<String, String> getParams() { 
       // Posting params to register url 
       Map<String, String> params = new HashMap<String, String>(); 
       params.put("tag", "vregister"); 
       params.put("name", name); 
       params.put("bname", bname); 
       params.put("address", location); 
       params.put("phoneno", phone); 
       params.put("website", website); 
       params.put("disc", disc); 
       params.put("ownerphone", ownerphone); 
       params.put("gname", gname); 
       params.put("latlong", latlong); 
       params.put("spinner", spinner); 
       return params; 
      } 
     }; 

     AppController.getInstance().addToRequestQueue(strReq, tag_string_req); 
    }

我使用PHP将数据插入到MySQL。

我的PHP代码

if($tag == 'vregister'){ 

      $vname =$_POST['name']; 
      $bname =$_POST['bname']; 
      $vaddress =$_POST['address']; 
      $vphoneno =$_POST['phoneno']; 
      $vwebsite =$_POST['website']; 
      $vdisc =$_POST['disc']; 
      $vownerphone =$_POST['ownerphone']; 
      $vgname =$_POST['gname']; 
      $vlatlong =$_POST['latlong']; 
      $vspinner =$_POST['spinner']; 

      $status='Pending'; 


      //insert and get response 
      $sql=$dbh->prepare("INSERT INTO `newvenderreq`(pname, bname, address, phone, website, ownerphone, disc, gname, latlng, date, status, spinner) VALUES (:pname, :bname, :address, :phone, :website, :ownerphone, :disc, :gname, :latlng, NOW(), :status, :spinner)"); 
      $sql->execute(array(':pname'=>$vname, 
           ':bname'=>$bname, 
           ':address'=>$vaddress, 
           ':phone'=>$vphoneno, 
           ':website'=>$vwebsite, 
           ':ownerphone'=>$vownerphone, 
           ':disc'=>$vdisc, 
           ':gname'=>$vgname, 
           ':latlng'=>$vlatlong, 
           ':status'=>$status, 
           ':spinner'=>$vspinner)); 

      if ($sql->rowCount() > 0) { 
       // user stored successfully 
       $response["error"] = FALSE; 
       //$response["uid"] = $user["id"]; 
       //$response["bname"]= $bname; 

       header('Content-Type:Application/json'); 
       $array[] = $response; 
       echo json_encode($array); 
      } else { 
       // user failed to store 
       $response["error"] = TRUE; 
       $response["error_msg"] = "Error occured in Registartion"; 
       echo json_encode($response); 
      } 

     }

来源

2017-06-27 Asesha George

$array[] = $response;

通$响应这里没有唯一的PHP代码的Android。和TBH，我甚至不确定问题中是否有MySQL代码。 –

什么是服务器响应 –

我得到的消息错误发生在注册 –

在PHP代码只是删除这一行json_encode($response);

来源

2017-06-27 13:46:23

如何知道什么值从我的Activity发送到MySql服务器在android

回答

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