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我有以下批处理脚本来替换提供的文本和一些其他文本。批处理脚本右括号问题
@echo off
setlocal
call :FindReplace %1 %2 %3
exit /b
:FindReplace <findstr> <replstr> <file>
set tmp="%temp%\tmp.txt"
If not exist %temp%\_.vbs call :MakeReplace
for /f "tokens=*" %%a in ('dir "%3" /s /b /a-d /on') do (
for /f "usebackq" %%b in (`Findstr /mic:"%~1" "%%a"`) do (
echo(&Echo Replacing "%~1" with "%~2" in file %%~nxa
<%%a cscript //nologo %temp%\_.vbs "%~1" "%~2">%tmp%
if exist %tmp% move /Y %tmp% "%%~dpnxa">nul
)
)
del %temp%\_.vbs
exit /b
:MakeReplace
>%temp%\_.vbs echo with Wscript
>>%temp%\_.vbs echo set args=.arguments
>>%temp%\_.vbs echo .StdOut.Write _
>>%temp%\_.vbs echo Replace(.StdIn.ReadAll,args(0),args(1),1,-1,1)
>>%temp%\_.vbs echo end with
现在,我正试图自动化构建和设置我的应用程序。我从下一批调用上述脚本。
@echo off
set a=C:\Program Files (x86)\Apache Software Foundation\Apache2.2\conf\httpd.conf
call Text_Replacer "branch-1" "branch-2" "%a%"
由于路径中的')',我在控制台中得到以下内容。
\Apache was unexpected at this time.
请帮我摆脱''''。
使用powershell。 – Ben