2011-05-27 104 views

回答

5

It's not exactly your situation, but contains what you need to know to do what you need to do:

<html xmlns="http://www.w3.org/1999/xhtml"> 
<head id="Head1" runat="server"> 
    <title></title> 
    <link rel="stylesheet" href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8.6/themes/base/jquery-ui.css" 
     type="text/css" media="all" /> 
    <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.4/jquery.min.js" type="text/javascript"></script> 
    <script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8.6/jquery-ui.min.js" 
     type="text/javascript"></script> 
    <script type="text/javascript"> 
     $(function() { 

      // 0 = monday, 1 = tuesday, 2 = wednesday, 3 = thursday, 
      // 4 = friday, 5 = saturday, 6 = sunday 

      var daysToDisable = [2, 4, 5]; 

      $('#<%= txtDate.ClientID %>').datepicker({ 
       beforeShowDay: disableSpecificWeekDays 
      }); 

      function disableSpecificWeekDays(date) { 
       var day = date.getDay(); 
       for (i = 0; i < daysToDisable.length; i++) { 
        if ($.inArray(day, daysToDisable) != -1) { 
         return [false]; 
        } 
       } 
       return [true]; 
      } 
     }); 
    </script> 
</head> 
<body> 
    <form id="form1" runat="server"> 
     <asp:TextBox ID="txtDate" runat="server"></asp:TextBox> 
    </form> 
</body> 
</html> 
12
// Enable Sunday only 
$("#datepickerID").datepicker({ 
    dateFormat: 'dd-mm-yy', 
    minDate: 1, 
    beforeShowDay: enableSUNDAYS 
}); 
// Custom function to enable SUNDAY only in jquery calender 
function enableSUNDAYS(date) { 
    var day = date.getDay(); 
    return [(day == 0), '']; 
} 
+0

你好,这种方法不是为我工作,我得到以下错误: p.apply不是一个函数 [在这个错误]解决方法1:t =(this._getFirstDayOfMonth(m,g)-h + ...()== N.getTime()&& g == a.selectedMonth &&在线531 jquery-ui文件任何帮助? – 2011-08-26 14:41:46

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