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我不知道如何合并很多信号并从RACTuple获得结果,它似乎像是简单的答案,但我找不到。从合并信号获取RACTuple
我们有〔实施例什么:
NSArray *a = @[@{@"k1":@"v1"},
@{@"k2":@"v2"},
@{@"k3":@"v3"},
@{@"k4":@"v4"},
@{@"k5":@"v5"},
@{@"k6":@"v6"},
@{@"k7":@"v7"}];
NSArray *b = @[@{@"kk1":@"vv1"},
@{@"kk2":@"vv2"},
@{@"kk3":@"vv3"},
@{@"kk4":@"vv4"},
@{@"kk5":@"vv5"},
@{@"kk6":@"vv6"},
@{@"kk7":@"vv7"}];
和
RACCommand *command = [[RACCommand alloc] initWithSignalBlock:^RACSignal *(id input) {
RACSignal *s1 = [self adaptObjects:a];
RACSignal *s2 = [self adaptObjects:b];
return [[RACSignal merge:@[s1,s2]] map:^id(id value) {
return [RACSignal createSignal:^RACDisposable *(id<RACSubscriber> subscriber) {
[subscriber sendNext:value];
return nil;
}];
}];
}];
[[command execute:nil] subscribeNext:^(RACTuple *x) {
NSLog(@"%@",x);
}];
该运营商map
是错了,我知道,但这是例如
- (RACSignal *)adaptObjects:(NSArray *)objects {
return [objects.rac_sequence.signal flattenMap:^RACStream *(id x) {
return [self adaptObject:x];
}];
}
- (RACSignal*)adaptObject:(NSDictionary*) x {
return [RACSignal createSignal:^RACDisposable *(id<RACSubscriber> subscriber) {
// some operations with data here
[subscriber sendNext:x];
return nil;
}];
}
在的NSLog我想首先看两个数组的元组结果 - s1,second - s2 Thx
是的,它很好的例子。我错过了我们可以用'return:'方法将任何对象包装到RACSignal的事实。谢谢 –