解析嵌套的JSON来检索嵌套的数组值

Question

我想从这个Json中获取一些特定的字段。我已经设法检索第一级中的那些，但我需要从数据字段中取出一些。我想获得以下数据字段的数组：

data = [(data artist id, data artist id name, and data rank), (data artist id, data artist id name, and data rank)...] 

例如：

data = [(ed61fe981f9143fe82536a0e5e9836f7, Rihanna, 1), (668dfb9383684b79ba603605db21ac51, PSY, 2)..] 

任何想法如何做到这一点？

的JSON是下面：

{ 
" response": { 
"class": "chart", 
"data": [ 
    { 
     "artist": { 
      "class": "artist", 
      "id": "ed61fe981f9143fe82536a0e5e9836f7", 
      "musicbrainz": "73e5e69d-3554-40d8-8516-00cb38737a1c", 
      "name": "Rihanna" 
     }, 
     "rank": 1, 
     "value": 42437.6397 
    }, 
    { 
     "artist": { 
      "class": "artist", 
      "id": "668dfb9383684b79ba603605db21ac51", 
      "musicbrainz": "f99b7d67-4e63-4678-aa66-4c6ac0f7d24a", 
      "name": "PSY" 
     }, 
     "rank": 2, 
     "value": 21562.2685 
    }, 

    … goes up to about 200 items 
    ], 

    "end_time": 1358553600, 
    "id": "396c5b836ce74200b2b5b8ba1df28956", 
    "name": "high_flyers_plays_total", 
    "next_id": null, 
    "now_id": "b857276b34cf488f9a934765c3281af7", 
    "period": 86400, 
    "previous_id": "cb566393058c4ddfa0b957063fbdc2e3", 
    "start_time": 1358467200 
    }, 
    "success": true 
    } 

这里是我的PHP代码：

<?php 


    //Chart json url 
    $url = "http://website.com"; 

    function get_json($url) 
    { 
     $ch = curl_init(); 

     //Very short time to get json so long timeout not needed 
     $timeout = 5; 
     curl_setopt($ch,CURLOPT_URL,$url); 
     curl_setopt($ch,CURLOPT_RETURNTRANSFER,1); 
     curl_setopt($ch,CURLOPT_CONNECTTIMEOUT,$timeout); 
     $data = curl_exec($ch); 
     curl_close($ch); 
     return $data; 
    } 


    $json = get_json($url); 

    $info = json_decode($json,true); 




//Prints the outer variables 

    print "This is the end_time for the chart : "; 
    print $info["response"]["end_time"]."<br />"; 

    print "This is the name for the chart : "; 
    print $info["response"]["name"]."<br />"; 

    print "This is the UUID of the chart : "; 
    print $info["response"]["id"]."<br />"; 


    print "This is the period for the chart : "; 
    print $info["response"]["period"]."<br />"; 

    /* gets the json data from the URL */ 




?> 

Answer 1

这个怎么样？

$stuff = json_decode($json, true); 

$results = array(); 

foreach($stuff['response']['data'] as $chunk) { 
    $artist = $chunk['artist']; 
    $id = $artist['id']; 
    $name = $artist['name']; 

    $rank = $chunk['rank']; 

    $tuple = array($id, $name, $rank); 

    $results[] = $tuple; 
}