MySQL - 比较同一表中的行与日期范围

我有一个MySQL查询的小问题。我需要比较同一个表中的行。这里是我的表 “video_stats”：MySQL - 比较同一表中的行与日期范围

---------------------------------- 
video  | date  | views 
---------------------------------- 
8kCge8vWnIg | 2017-05-15 | 4 
8kCge8vWnIg | 2017-05-16 | 20 
8kCge8vWnIg | 2017-05-17 | 11 
8kCge8vWnIg | 2017-05-18 | 12 
rYyiTP0srNs | 2017-05-15 | 627 
rYyiTP0srNs | 2017-05-16 | 6414 
rYyiTP0srNs | 2017-05-17 | 21076 
rYyiTP0srNs | 2017-05-18 | 34434 
cRfEo-ZzU4U | 2017-05-17 | 17049 
cRfEo-ZzU4U | 2017-05-18 | 12466

MySQL查询：

SELECT t1.video, 
     t1.date, 
     t1.views, 
     t1c.video, 
     t1c.date, 
     t1c.views 
FROM video_stats t1 
LEFT JOIN video_stats t1c ON t1.video=t1c.video 
      AND t1c.date<='2017-05-16' AND t1c.date>='2017-05-15' 
WHERE t1.date>='2017-05-17' 
     AND t1.date<='2017-05-18'

结果是在这里...

 -------------------------------------------------------------------------- 
    video  | t1.date | t1.views | video  | t1c.date | t1c.date 
    -------------------------------------------------------------------------- 
#1| 8kCge8vWnIg | 2017-05-17 | 12  | 8kCge8vWnIg | 2017-05-15 | 4 
#2| 8kCge8vWnIg | 2017-05-17 | 12  | 8kCge8vWnIg | 2017-05-16 | 20 
#3| 8kCge8vWnIg | 2017-05-18 | 11  | 8kCge8vWnIg | 2017-05-15 | 4 
#4| 8kCge8vWnIg | 2017-05-18 | 11  | 8kCge8vWnIg | 2017-05-16 | 20 
#5| rYyiTP0srNs | 2017-05-17 | 21076 | rYyiTP0srNs | 2017-05-15 | 627 
#6| rYyiTP0srNs | 2017-05-17 | 21076 | rYyiTP0srNs | 2017-05-16 | 6414 
#7| rYyiTP0srNs | 2017-05-18 | 34434 | rYyiTP0srNs | 2017-05-15 | 627 
#8| rYyiTP0srNs | 2017-05-18 | 34434 | rYyiTP0srNs | 2017-05-16 | 6414 
#9| cRfEo-ZzU4U | 2017-05-17 | 17049 | NULL  | NULL  | NULL 
#10| cRfEo-ZzU4U | 2017-05-18 | 12466 | NULL  | NULL  | NULL

没有与两个T1单日期没有问题。日期和t1c.date。但是如果有多个日期，问题就会开始。如何排除重复的行：＃2和＃3，＃6和＃7？ 如何恰当地总结t1.views和t1c.views？

最后，我需要这样的东西......但我不知道如何。

video  | t1.views *05/17 + 05/18* | t1c.views *05/15 + 05/16* 
------------------------------------------------------------------- 
8kCge8vWnIg | 23      | 24 
rYyiTP0srNs | 55510     | 7041 
cRfEo-ZzU4U | 29515     | NULL

来源

2017-05-23 Andrei Bely

恶心，但它的工作原理：

select 
    r1.video, 
    r1.views, 
    r2.views 
from 
    (SELECT 
     t1.video, 
     sum(t1.views) as views 
    FROM 
     test t1 
    WHERE 
     t1.date>='2017-05-17' 
     AND t1.date<='2017-05-18' 
     group by t1.video) r1 
    left outer join 
    (SELECT 
     t2.video, 
     sum(t2.views) as views 
    FROM 
     test t2 
    WHERE 
     t2.date>='2017-05-15' 
     AND t2.date<='2017-05-16' 
     group by t2.video) r2 
    on r1.video = r2.video;

来源

2017-05-24 00:26:39 ghenghy

TNX，它工作得很好。有点慢（尤其是大日期范围），但我想没有办法改善查询。 –

select a.Video,a.views as 'view *05/15 + 05/16*',b.views as 'iew *05/17 + 05/18*' from 
(select Video,sum(views) as views from 
(SELECT * FROM YOURTABLE) as a where date(`date`)>='2017-05-17' and date(`date`)<='2017-05-18' 
GROUP BY Video) as a 

left join 

(select Video,sum(views) as views from 
(SELECT * FROM YOURTABLE) as a where date(`date`)>='2017-05-15' and date(`date`)<='2017-05-16' 
GROUP BY Video) as b 
on a.Video = b.Video

测试结果：

8kCge8vWnIg 23  24 
cRfEo-ZzU4U 29515 
rYyiTP0srNs 55510 7041

来源

2017-05-24 02:20:43

MySQL - 比较同一表中的行与日期范围

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