用扫描仪捕捉空间？

Question

我有一系列的问题需要创建一副闪存卡。到目前为止，只要问题没有空格，我可以收集问题和答案。如果问题确实有空格，答案会被跳过，但如果答案有空格，则没有问题。这里是我的代码片段：

 
    System.out.println("What is the question for number " + (cards + 1) + "?"); 
    question = in.next(); 
    System.out.println("What is the answer for number " + (cards + 1) + "?"); 
    answer = in.next(); 

，这里是用空格输出结果的问题和答案：

What is the question for number 1? 
This is a question 
What is the answer for number 1? 
What is the question for number 2? 
x 
What is the answer for number 2? 
This is an answer 
What is the question for number 3? 
X 

Answer 1

而不是使用next()方法，使用nextLine()捕捉到整条生产线，而不是只是下一个字：

System.out.println("What is the question for number " + (cards + 1) + "?"); 
question = in.nextLine(); 
System.out.println("What is the answer for number " + (cards + 1) + "?"); 
answer = in.nextLine(); 

这有帮助吗？

Answer 2

next（）只读取输入直到空格。它无法读取由空格分隔的单词。

nextLine（）读取输入，包括单词之间的空格（它直到行尾）