我一直在试图填补我的谷歌图表动态地,像这样的例子: https://developers.google.com/chart/interactive/docs/php_example谷歌图 - 填充与JSON
我用这依赖于DataTable类及其他:
<dependency>
<groupId>com.google.visualization</groupId>
<artifactId>visualization-datasource</artifactId>
<version>1.1.1</version>
</dependency>
这是DataTable类的API: https://developers.google.com/chart/interactive/docs/dev/dsl_javadocs/com/google/visualization/datasource/datatable/DataTable
我使用Java的HttpServlet包含此代码(例如)来填充数据表:
DataTable dataTable = new DataTable();
dataTable.addColumn(new ColumnDescription("uur", ValueType.TEXT, "Uur"));
dataTable.addColumn(new ColumnDescription("aantal", ValueType.NUMBER, "Aantal spellen"));
try {
dataTable.addRowFromValues("1", 5, true);
dataTable.addRowFromValues("2", 9, true);
dataTable.addRowFromValues("3", 17, true);
} catch (TypeMismatchException ex) {
Logger.getLogger(VerkrijgChartDataServlet.class.getName()).log(Level.SEVERE, null, ex);
}
我也包括在此使其返回JSON:
response.setContentType("application/json");
然后用GSON我将其转换为一个JSON字符串:
new Gson().toJson(dataTable);
这将返回格式的字符串:
{
"columnIndexById" : {"aantal":1, "uur":0},
"columns" : [
{"id":"uur","label":"Uur","pattern":"","type":"TEXT"},
{"id":"aantal","label":"Aantal spellen","pattern":"","type":"NUMBER"}
],
"rows" : [
{"cells":[{"value":{"value":"1"}},{"value":{"value":5.0}}]},
{"cells":[{"value":{"value":"2"}},{"value":{"value":9.0}}]},
{"cells":[{"value":{"value":"3"}},{"value":{"value":17.0}}]},
],
"warnings" : []
}
但是Google Chart却说:'Table has no col UMS“。 谷歌的例子JSON看起来是这样的:
{
"cols": [
{"id":"","label":"Topping","pattern":"","type":"string"},
{"id":"","label":"Slices","pattern":"","type":"number"}
],
"rows": [
{"c":[{"v":"Mushrooms","f":null},{"v":3,"f":null}]},
{"c":[{"v":"Onions","f":null},{"v":1,"f":null}]},
{"c":[{"v":"Olives","f":null},{"v":1,"f":null}]},
{"c":[{"v":"Zucchini","f":null},{"v":1,"f":null}]},
{"c":[{"v":"Pepperoni","f":null},{"v":2,"f":null}]}
]
}
有没有人有什么我做错了的想法?我需要做其他事吗? Thanx提前。