2014-04-05 32 views

回答

1
select sum(instr(some_column, '@gmail.com') > 0) as gmail_count 
from your_table 
+0

喜克林斯曼,这是更快LIKE opeartor或INSTR()function..thnx –

+0

你可以试试。使用'explain select ...'并查看哪个查询执行得更好。 –

2
SELECT COUNT(*) as numGmailAccounts 
FROM tableName 
WHERE emailColumn like '%gmail.com' 
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