有没有办法让MS Access抓取当前的Active Directory用户？

Question

我正在为我公司的一个软件开发一个规范，并且作为审计系统的一部分，我认为如果有办法获取当前的Active Directory用户，它会很整洁。

希望是这样的：

Dim strUser as String 
strUser = ActiveDirectory.User() 
MsgBox "Welcome back, " & strUser 

Answer 1

Try this article - 我有，将企业风险管理，工作，如果这不起作用的一些代码...

相关报价：

Private Declare Function GetUserName Lib "advapi32.dll" Alias "GetUserNameA" _ 
        (ByVal IpBuffer As String, nSize As Long) As Long 
Private Declare Function GetComputerName Lib "kernel32" Alias "GetComputerNameA" _ 
        (ByVal lpBuffer As String, nSize As Long) As Long 

Function ThisUserName() As String 
    Dim LngBufLen As Long 
    Dim strUser As String 

    strUser = String$(15, " ") 
    LngBufLen = 15 

    If GetUserName(strUser, LngBufLen) = 1 Then 
     ThisUserName = Left(strUser, LngBufLen - 1) 
    Else 
     ThisUserName = "Unknown" 
    End If 
End Function 

Function ThisComputerID() As String 
    Dim LngBufLen As Long 
    Dim strUser As String 

    strUser = String$(15, " ") 
    LngBufLen = 15 

    If GetComputerName(strUser, LngBufLen) = 1 Then 
     ThisComputerID = Left(strUser, LngBufLen) 
    Else 
     ThisComputerID = 0 
    End If 
End Function 

Answer 2

取决于环境变量保持有效是一个坏主意，因为它们可以在用户会话中轻松更改。

Answer 3

David对使用环境变量的风险提出了一个非常好的观点。我只能补充说环境变量可能存在其他问题。只要看看这个实际的代码片段从我们5岁的项目：

Public Function CurrentWorkbenchUser() As String 

    ' 2004-01-05, YM: Using Application.CurrentUser for identification of 
    ' current user is very problematic (more specifically, extremely 
    ' cumbersome to set up and administer for all users). 
    ' Therefore, as a quick fix, let's use the OS-level user's 
    ' identity instead (NB: the environment variables used below must work fine 
    ' on Windows NT/2000/2003 but may not work on Windows 98/ME) 
    ' CurrentWorkbenchUser = Application.CurrentUser 
    ' 
    ' 2005-06-13, YM: Environment variables do not work in Windows 2003. 
    ' Use Windows Scripting Host (WSH) Networking object instead. 
    ' CurrentWorkbenchUser = Environ("UserDomain") & "\" & Environ("UserName") 
    ' 
    ' 2007-01-23, YM: Somewhere between 2007-01-09 and 2007-01-20, 
    ' the WshNetwork object stopped working on CONTROLLER3. 
    ' We could not find any easy way to fix that. 
    ' At the same time, it turns out that environment variables 
    ' do work on Windows 2003. 
    ' (Apparently, it was some weird configuration problem back in 2005: 
    ' we had only one Windows 2003 computer at that time and it was 
    ' Will's workstation). 
    ' 
    ' In any case, at the time of this writing, 
    ' returning to environment variables 
    ' appears to be the simplest solution to the problem on CONTROLLER3. 
    ' Dim wshn As New WshNetwork 
    ' CurrentWorkbenchUser = wshn.UserDomain & "\" & wshn.UserName 

    CurrentWorkbenchUser = Environ("USERDOMAIN") & "\" & Environ("USERNAME") 

End Function 

Answer 4

这里是我的版本：它会取你喜欢的东西：

'gets firstname, lastname, fullname or username 
Public Function GetUser(Optional whatpart = "username") 
    Dim returnthis As String 
    If whatpart = "username" Then GetUser = Environ("USERNAME"): Exit Function 
    Set objSysInfo = CreateObject("ADSystemInfo") 
    Set objUser = GetObject("LDAP://" & objSysInfo.USERNAME) 
    Select Case whatpart 
     Case "fullname": returnthis = objUser.FullName 
     Case "firstname", "givenname": returnthis = objUser.givenName 
     Case "lastname": returnthis = objUser.LastName 
     Case Else: returnthis = Environ("USERNAME") 
    End Select 
    GetUser = returnthis 
End Function 

I got the original idea from Spiceworks。