2014-01-23 29 views
1

我想要显示当我的List的结果= 1时从List获得的数据。我需要获得FileName,TitleHotspotID在C#中显示来自列表的数据

有人可以帮我吗?我需要帮助的部分在我的代码的最后部分。

这里是代码:

private void PerformSheetLink(String hotspotID, Int32 fileRec) 
    { 
     string nomenclature = dataLayer.GetNomenclature(fileRec, hotspotID); 
     string pattern = @"\((?<ProjectRec>\d+(?:_)?\d*?)*\,(?<FileName>[^,]*)\,(?<HotspotID>[^)]*)\)"; 
     Regex regex = new Regex(pattern, RegexOptions.Compiled); 
     Match m = regex.Match(nomenclature); 

     //Multiple numenclature exist   
     if (regex.Matches(nomenclature).Count > 1) 
     { 
      List<P2Trace> linkList = new List<P2Trace>(); 
      string fileName, hotspot, title;     
      MatchCollection mc = regex.Matches(nomenclature); 
      foreach (Match match in mc) 
      { 
       //This match has a Single Project 
       GroupCollection gc = match.Groups; 
       if (gc["ProjectRec"].Captures.Count == 1) 
       { 
        if ((int)cbModel.SelectedValue == Int32.Parse(gc["ProjectRec"].Value)) 
        { 
         fileName = String.Format("{0}.cgm", gc["FileName"].Value); 
         title = dataLayer.GetSheetTitle(fileName); 
         hotspot = FixHotspotID(gc["HotspotID"].Value); 
         linkList.Add(new P2Trace { FileName = fileName, HotspotID = hotspot, Title = title }); 
        } 
       } 
       else 
       { 
        //This match has Multiple Projects 
        List<Int32> pRecs = GetProjectRecsInList(gc["ProjectRec"].Captures); 
        if (pRecs.Contains((int)cbModel.SelectedValue)) 
        { 
         foreach (Int32 projectRecNo in pRecs) 
         { 
          if (projectRecNo == (int)cbModel.SelectedValue) 
          { 
           fileName = String.Format("{0}.cgm", gc["FileName"].Value); 
           title = dataLayer.GetSheetTitle(fileName); 
           hotspot = FixHotspotID(gc["HotspotID"].Value); 
           linkList.Add(new P2Trace { FileName = fileName, HotspotID = hotspot, Title = title }); 
          } 
         } 
        } 
       } 
      } 
      //Link found and collected, perform jump 
      if (linkList.Count == 1) 
      { 
       p2Trace.FileName = linkList. ????? 
       p2Trace.Title = linkList. ?????? 
       p2Trace.HotspotID= linkList. ?????? 
       jumpTo(p2Trace.FileName, p2Trace.Titel, p2Trace.HotspotID); 

      } 
+0

这是你的意图,只叫'jumpTo'如果你准确地找到一个匹配?如果发现两场比赛会发生什么? –

+0

我已经照顾过那部分,我只是没有发布代码 –

回答

1
p2Trace.FileName = linkList[0].FileName; 
p2Trace.Title = linkList[0].Title; 
p2Trace.HotspotID = linkList[0].HotspotID; 
0

尝试......

if (linkList.Count == 1) 
    { 
var firstItem = linkList[0]; 
     p2Trace.FileName = firstItem.FileName; 
     p2Trace.Title = firstItem.Title; 
     p2Trace.HotspotID= firstItem.HostspotID; 
     jumpTo(p2Trace.FileName, p2Trace.Titel, p2Trace.HotspotID); 

    } 
+0

工作正常。谢谢您的帮助 –

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