PHP MySQL脚本错误？

Question

我有以下PHP代码，我似乎无法工作。我一遍又一遍地查看错误，但无法找到它/它们。

<?php 
$actkey = rand() . "\n"; 
$con = mysql_connect("HOST", "USER", "PASS"); 
if (!$con) 
    { 
    die('Unable to connect: ' . mysql_error()); 
    } 

mysql_select_db("TABLE", $con); 

mysql_query("UPDATE members SET Activation = $actkey WHERE username = 'admin'"); 
mysql_close($con) 

$con2 = mysql_connect("HOST" , "USER" , "PASS"); 
if (!$con2) 
    { 
    die('Unable to connect: ' . mysql_error()); 
    } 
mysql_select_db("a1719745_insaneb", $con2); 
$query = mysql_query("INSERT INTO Activation (keycode, valid) VALUES ($actkey, 'yes')"); 
if(!mysql_query($query, $con2)) { 
    die('Error: ' . mysql_error()); 
} 
mysql_close($con2); 
echo "Complete"; 
?> 

任何想法？

Answer 1

mysql_close($con)后面有一个缺失的分号。