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我使用XAMPP的服务器和好吧,我似乎无法上传图片,如编辑的文档上传图片给我看......这里是链接: http://editor.froala.com/server-integrations/php-image-upload无法从froala编辑
我已经调查过这个问题,他们都说所有的链接都是不正确的,因为你需要把绝对网址放在那里,但即使这似乎并不奏效。
下面是代码: JS
$(document).ready(function(){
$('textarea').editable({inlineMode: false, height:200, imageUploadURL: 'upload_image.php', imageErrorCallback: function (data) {
// Bad link.
console.log(data);
}
});
});
upload_image.php:
<?php
// Allowed extentions.
$allowedExts = array("gif", "jpeg", "jpg", "png");
// Get filename.
$temp = explode(".", $_FILES["file"]["name"]);
// Get extension.
$extension = end($temp);
// An image check is being done in the editor but it is best to
// check that again on the server side.
// Do not use $_FILES["file"]["type"] as it can be easily forged.
$finfo = finfo_open(FILEINFO_MIME_TYPE);
$mime = finfo_file($finfo, $_FILES["file"]["tmp_name"]);
if ((($mime == "image/gif")
|| ($mime == "image/jpeg")
|| ($mime == "image/pjpeg")
|| ($mime == "image/x-png")
|| ($mime == "image/png"))
&& in_array($extension, $allowedExts)) {
// Generate new random name.
$name = sha1(microtime()) . "." . $extension;
// Save file in the uploads folder.
move_uploaded_file($_FILES["file"]["tmp_name"], "C:\ xampp\htdocs\Swaggy\img\ " . $name);
// Generate response.
$response = new StdClass;
$response->link = "/swaggy/img/" . $name;
echo stripslashes(json_encode($response));
}
当我尝试上传他形成在编辑器中img标签在基地64个,然后自败的图像。调试器显示我,upload_image.php有200种状态,并显示我从控制台错误的文件是这样的: Object {code: 4, message: "Parsing response failed"}
是的,我终于找到了一种方法如何从在调试Ajax调用检查后......是的,你说得对的功能是不确定的 “致命错误:调用未定义的函数finfo_open()” 的问题是我的PHP版本是5.5 ...我忘了一些东西? 顺便说一句谢谢一堆 – RazorEdge347 2014-09-30 17:09:19
请参阅http://stackoverflow.com/questions/3579072/php-fileinfo-is-undefined-function。看起来你必须在Windows上手动启用它。 – st3fan 2014-10-01 00:09:08
在给我链接之前,我解决了问题,现在它正在运行,感谢您的关注和帮助 – RazorEdge347 2014-10-01 11:50:34