获得所有组从用户 - sfDoctrineGuardPlugin

Question

在sfDoctrineGuardPlugin是：

sfGuardUser: 
    actAs: [Timestampable] 
    columns: 
    first_name: string(255) 
    last_name: string(255) 
    // 
    indexes: 
    is_active_idx: 
     fields: [is_active] 
    relations: 
    Groups: 
     class: sfGuardGroup 
     local: user_id 
     foreign: group_id 
     refClass: sfGuardUserGroup 
     foreignAlias: Users 



sfGuardGroup: 
    actAs: [Timestampable] 
    columns: 
    name: 
     type: string(255) 
     unique: true 
    description: string(1000) 
    relations: 
    Users: 
     class: sfGuardUser 
     refClass: sfGuardUserGroup 
     local: group_id 
     foreign: user_id 
     foreignAlias: Groups 

sfGuardUserGroup: 
    options: 
    symfony: 
     form: false 
     filter: false 
    actAs: [Timestampable] 
    columns: 
    user_id: 
     type: integer 
     primary: true 
    group_id: 
     type: integer 
     primary: true 
    relations: 
    User: 
     class: sfGuardUser 
     local: user_id 
     onDelete: CASCADE 
    Group: 
     class: sfGuardGroup 
     local: group_id 
     onDelete: CASCADE 

这是关系到很多很多，我怎么能得到用户的所有组？

• @method Doctrine_Collection
  getGroups（）返回 当前记录的 “组” 收集

我做：

$this->groups = $this->getUser()->getGuardUser()->getGroups(); 

这个回报：

 Doctrine_Collection data : Array()

我如何检查用户是否在组测试？

感谢您的帮助！

Answer 1

见sfGuardSecurityUser类：https://github.com/Garfield-fr/sfDoctrineGuardPlugin/blob/master/lib/user/sfGuardSecurityUser.class.php

if ($this->getUser()->hasGroup('TEST')) { 
    //if user is on group TEST 
}//end if 

// get all groups 

$userGroups = $this->getUser()->getGroups(); 

Answer 2

您可以尝试使用查询找到你的用户群：

$user_id = $this->getUser()->getGuardUser()->getId(); 
$groups = Doctrine_core::getTable('sfGuardGroup')->create_query('g')->innerJoin('g.users u with u.id= ?', $user_id);