如何使用循环打印卡片？

Question

我已经设置了所有52张卡，并且我尝试使用for loop打印所有52张卡。 我不知道如何设置我的for loop在这一点上。

def define_cards(n): 
    rank_string = ("ace","two","three","four","five","six","seven","eight","nine","ten","jack","queen","king") 
    suit_string = ("clubs","diamonds","hearts","spades") 
    cards = [] 
    for suit in range(4): 
     for rank in range(13): 
      card_string = rank_string[rank] + " of " + suit_string[suit] 
      cards.append(card_string) 

print "The cards are:" 
for i in range(52):    #how to make this for loop work?? 
    print i, card_string[i] 

我想打印这样

The crads are: 
0 ace of clubs 
1 two of clubs 
2 three of clubs 
... 
49 jack of spades 
50 queen of spades 
51 king of spades 

Answer 1

你的功能define_cards必须返回列表中。在末尾添加return cards。

然后你必须实际调用/执行这个函数。

然后你就可以访问各个卡在这个名单：

cards = define_cards() 
for i, card in enumerate(cards): 
    print i, card 

不过，如果你正在寻找一个“更Python”的解决方案，试试这个：

import itertools as it 

rank_string = ("ace","two","three","four","five","six","seven","eight","nine","ten","jack","queen","king") 
suit_string = ("clubs","diamonds","hearts","spades") 

print 'The cards are:' 
for i, card in enumerate(it.product(rank_string, suit_string)): 
    print i, '{0[1]} of {0[0]}'.format(card) 

Answer 2

为什么不使用迭代器：

def define_cards(): 
    rank_string = ("ace","two","three","four","five","six","seven","eight","nine","ten","jack","queen","king") 
    suit_string = ("clubs","diamonds","hearts","spades") 
    for suit in suit_string:  # you can obtain the items of the iterate list directly, no need of rank access 
     for rank in rank_string: 
      card_string = rank + " of " + suit 
      yield card_string 

print "The cards are:" 
cards_iterator = define_cards() 
for i, card in enumerate(cards_iterator): # use the iterator power ;) 
    print i, card 

Answer 3

看看眼前这个

cards.append(card_string) 

print "The cards are:" 
for i in range(52):    #how to make this for loop work?? 
    print i, card_string[i] 

为什么要打印card_string[i]？

cards[i]怎么了？

Answer 4

ranks = ("ace","two","three","four","five","six","seven","eight","nine","ten","jack","queen","king") 
suits = ("clubs","diamonds","hearts","spades") 

回答是优雅的单行：

cards = [rank+' of '+suit for suit in suits for rank in ranks] 

for i,card in enumerate(cards): 
    print i, card 

结果：

0 ace of clubs 
1 two of clubs 
... 
50 queen of spades 
51 king of spades 

Answer 5

def define_cards(): 
    rank_string = ("ace","two","three","four","five","six","seven","eight","nine","ten","jack","queen","king") 
    suit_string = ("clubs","diamonds","hearts","spades") 
    cards = [] 
    n = 0 
    for suit in suit_string: 
     for rank in rank_string: 
      print '%s %s of %s' % (n,rank,suit) 
      n+=1 

define_cards()