我在PHP中遇到这个问题,当我尝试将数组转换为json时 我有一个递归函数,它构建数组并将其编码为jSon格式。JSON问题需要帮助
这就是数组:
$data = array(
array('id' => 1, 'parent_id' => null, 'text' => 'lorem ipsum'),
array('id' => 2, 'parent_id' => 1, 'text' => 'lorem ipsum1'),
array('id' => 3, 'parent_id' => 1, 'text' => 'lorem ipsum2'),
array('id' => 4, 'parent_id' => 2, 'text' => 'lorem ipsum3'),
array('id' => 5, 'parent_id' => 3, 'text' => 'lorem ipsum4'),
array('id' => 6, 'parent_id' => null, 'text' => 'lorem ipsum5'),
);
这就是我的功能:
function trataArray($data) {
$itemsByReference = array();
// Build array of item references:
foreach ($data as $key => &$item) {
$itemsByReference[$item['id']] = &$item;
// Children array:
$itemsByReference[$item['id']]['children'] = array();
// Empty data class (so that json_encode adds "data: {}")
$itemsByReference[$item['id']]['data'] = new StdClass();
}
// Set items as children of the relevant parent item.
foreach ($data as $key => &$item)
if ($item['parent_id'] && isset($itemsByReference[$item['parent_id']]))
$itemsByReference [$item['parent_id']]['children'][] = &$item;
// Remove items that were added to parents elsewhere:
foreach ($data as $key => &$item) {
if ($item['parent_id'] && isset($itemsByReference[$item['parent_id']]))
unset($data[$key]);
}
// Encode:
return $data;
}
那是我的JSON,但此JSON有错误:
{
"0": // Problem here... T_T
{
"id": 1,
"parent_id": null,
"name": "lorem ipsum",
"children": [
{
"id": 2,
"parent_id": 1,
"name": "lorem ipsum1",
"children": [
{
"id": 4,
"parent_id": 2,
"name": "lorem ipsum3",
"children": [],
"data": {}
}
],
"data": {}
},
{
"id": 3,
"parent_id": 1,
"name": "lorem ipsum2",
"children": [
{
"id": 5,
"parent_id": 3,
"name": "lorem ipsum4",
"children": [],
"data": {}
}
],
"data": {}
}
],
"data": {}
},
"5": // And here... T_T
{
"id": 6,
"parent_id": null,
"name": "lorem ipsum5",
"children": [],
"data": {}
}
}
琴弦“0”:和“5”:都是ca在json标记中使用错误。 我认为尝试使用preg_replace删除它,但我很糟糕的正则表达式工作。有人可以帮助我吧...:D
谢谢你们!
我有一个想法... :)
我一直在寻找各种方法来测试变薄屎...:d 。我来这里有一个想法,从插件和ENCODE得到JSON它作为一个数组并打印出来,看看我需要给JSON Encode来给我正确的东西。
他们,他重现:
Array
(
[0] => stdClass Object
(
[id] => 1
[text] => City
[children] => Array
(
[0] => stdClass Object
(
[id] => 11
[text] => Wyoming
[children] => Array
(
[0] => stdClass Object
(
[id] => 111
[text] => Albin
)
[1] => stdClass Object
(
[id] => 112
[text] => Canon
)
[2] => stdClass Object
(
[id] => 113
[text] => Egbert
)
)
)
[1] => stdClass Object
(
[id] => 12
[text] => Washington
[state] => closed
[children] => Array
(
[0] => stdClass Object
(
[id] => 121
[text] => Bellingham
)
[1] => stdClass Object
(
[id] => 122
[text] => Chehalis
)
[2] => stdClass Object
(
[id] => 123
[text] => Ellensburg
)
[3] => stdClass Object
(
[id] => 124
[text] => Monroe
)
)
)
)
)
)
的JSON其上的对象的基础上,我认为它的存在的bug,IM tryng使用数组的工作,并将其转换,当数据的对象。
有人知道如何创建类似的东西? 只是一个方式我能想到的...谢谢家伙...
:DDD
而不是将整个东西转换成JSON,使用一个循环,并将每个迭代转换成JSON。 – Ibu
p.s.使用'foreach()'引用时要非常小心;看到这个评论的例子:http://www.php.net/manual/en/control-structures.foreach.php#101425 – ken
我会认为删除“1”和“5”会使它无效的JSON。为什么不按照你希望JSON数据结构来构建原始数据结构,而不是试图将一个数据结构转换成完全不同的数据结构? – dqhendricks