对于AS3来说,读取和存储数据的方式是最快的。对于现在的调试,它只是读取原始XML,但我怀疑如果我将它们变成嵌套数组,它会更快。在AS3中存储和解析数据的最有效方式是什么?
将XML解析为嵌套数组以供稍后阅读是最有效的方法?还是有更好的方法来读取大量数据?
对于AS3来说,读取和存储数据的方式是最快的。对于现在的调试,它只是读取原始XML,但我怀疑如果我将它们变成嵌套数组,它会更快。在AS3中存储和解析数据的最有效方式是什么?
将XML解析为嵌套数组以供稍后阅读是最有效的方法?还是有更好的方法来读取大量数据?
好pasring一个xml到数组具有各种优势,如上面提到的意见.. 您将如何得到嵌套数组的示例XML
<mynode4 swf="node4.swf" htmlpage="">
<subheading1 swf="L4_s1.swf" htmlpage="L4_1.htm">Work Hard</subheading1>
<subheading2 swf="L4_s2.swf" htmlpage="L4_2.htm">karachi</subheading2>
<subheading3 swf="L4_s3.swf" htmlpage="L4_3.htm">Newyork City.</subheading3>
</mynode4>
<mynode5 swf="five.swf" htmlpage="">Here is the Test for node 5</mynode5>
<mynode6 swf="six.swf" htmlpage="">Last node accessed</mynode6>
VAR uLoader:的URLLoader = new URLLoader() uLoader.addEventListener(Event.COMPLETE,onXMLLoaded) uLoader.load(new URLRequest(“xmldata.xml”))
公共函数onXMLLoaded(事件:事件):无效{
var loader:URLLoader = URLLoader(event.target);
var root1:XML = new XML(loader.data);
var showChilds:XMLList = root1.children();
var nodes_names2 :Array = new Array();
var nodes_swf2 :Array = new Array();
var nodes_values2 :Array = new Array();
var nodes_pages2 :Array = new Array();
var take_items:Array = recursiveXML(showChilds,nodes_names2,nodes_swf2,nodes_values2,nodes_pages2,0);
this.nodes_names2 = take_items[0];
this.nodes_swf2 = take_items[1];
this.nodes_values2 = take_items[2];
this.nodes_pages2 = take_items[3];
trace(nodes_names2);
trace(nodes_swf2);
trace(nodes_values2);
trace(nodes_pages2);
}
公共函数recursiveXML(showChilds:XMLList中,nodes_names:阵列,nodes_swf:阵列,nodes_values:阵列,nodes_pages:阵列, count:int):Array {
for each (var eachChild:XML in showChilds)
{
if(eachChild.hasComplexContent())
{
nodes_names[count] = new Array((eachChild.children().length()))
nodes_swf[count] = new Array((eachChild.children().length()))
nodes_values[count] = new Array((eachChild.children().length()))
nodes_pages[count] = new Array((eachChild.children().length()))
nodes_names[count][0] = eachChild.name()
nodes_swf[count][0] = eachChild.attribute("swf");
nodes_values[count][0] = "";
nodes_pages[count][0] = "";
var showChilds:XMLList = eachChild.children();
var take_items:Array = recursiveXML(showChilds,nodes_names[count],nodes_swf[count],nodes_values[count],nodes_pages[count] , 1);
nodes_names[count] = take_items[0];
nodes_swf[count] = take_items[1];
nodes_values[count] = take_items[2];
nodes_pages[count] = take_items[3];
count++;
}
else
{
nodes_names[count] = eachChild.name();
nodes_swf[count] = eachChild.attribute("swf");
nodes_pages[count] = eachChild.attribute("htmlpage");
nodes_values[count] = eachChild.text();
count++;
}
}
var _items:Array = new Array(nodes_names, nodes_swf,nodes_values,nodes_pages);
return _items;
}
第一次解析XML时,您可以将数据存储在Object中,以便随后在需要时更容易/更快地检索一组属性。
如果您愿意,可以将此对象视为多维数组。
与Array.sortOn方法结合使用时,转换为对象也可能会有所帮助。您也可以考虑使用JSON作为传输格式;它将消除解析和转换XML的开销。
定义“大量数据”。 – Raveline 2010-09-22 08:56:18