2010-09-22 47 views
1

对于AS3来说,读取和存储数据的方式是最快的。对于现在的调试,它只是读取原始XML,但我怀疑如果我将它们变成嵌套数组,它会更快。在AS3中存储和解析数据的最有效方式是什么?

将XML解析为嵌套数组以供稍后阅读是最有效的方法?还是有更好的方法来读取大量数据?

+1

定义“大量数据”。 – Raveline 2010-09-22 08:56:18

回答

1

好pasring一个xml到数组具有各种优势,如上面提到的意见.. 您将如何得到嵌套数组的示例XML

<mynode4 swf="node4.swf" htmlpage=""> 
<subheading1 swf="L4_s1.swf"  htmlpage="L4_1.htm">Work Hard</subheading1> 
<subheading2 swf="L4_s2.swf"  htmlpage="L4_2.htm">karachi</subheading2> 
<subheading3 swf="L4_s3.swf"  htmlpage="L4_3.htm">Newyork City.</subheading3> 
</mynode4>  
<mynode5 swf="five.swf" htmlpage="">Here is the Test for node 5</mynode5> 
<mynode6 swf="six.swf" htmlpage="">Last node accessed</mynode6> 

VAR uLoader:的URLLoader = new URLLoader() uLoader.addEventListener(Event.COMPLETE,onXMLLoaded) uLoader.load(new URLRequest(“xmldata.xml”))

公共函数onXMLLoaded(事件:事件):无效{

var loader:URLLoader = URLLoader(event.target); 
    var root1:XML = new XML(loader.data); 
    var showChilds:XMLList = root1.children(); 
    var nodes_names2   :Array = new Array(); 
    var nodes_swf2    :Array = new Array(); 
    var nodes_values2   :Array = new Array(); 
    var nodes_pages2   :Array = new Array(); 


    var take_items:Array = recursiveXML(showChilds,nodes_names2,nodes_swf2,nodes_values2,nodes_pages2,0); 
    this.nodes_names2  = take_items[0]; 
    this.nodes_swf2   = take_items[1]; 
    this.nodes_values2  = take_items[2]; 
    this.nodes_pages2  = take_items[3]; 

    trace(nodes_names2); 
    trace(nodes_swf2); 
    trace(nodes_values2); 
    trace(nodes_pages2); 

}

公共函数recursiveXML(showChilds:XMLList中,nodes_names:阵列,nodes_swf:阵列,nodes_values:阵列,nodes_pages:阵列, count:int):Array {

 for each (var eachChild:XML in showChilds) 
     { 
      if(eachChild.hasComplexContent()) 
      { 
       nodes_names[count]   = new Array((eachChild.children().length())) 
       nodes_swf[count]   = new Array((eachChild.children().length())) 
       nodes_values[count]   = new Array((eachChild.children().length())) 
       nodes_pages[count]   = new Array((eachChild.children().length())) 

       nodes_names[count][0]  = eachChild.name() 
       nodes_swf[count][0]   = eachChild.attribute("swf"); 
       nodes_values[count][0]  = ""; 
       nodes_pages[count][0]  = ""; 
       var showChilds:XMLList  = eachChild.children(); 
       var take_items:Array  = recursiveXML(showChilds,nodes_names[count],nodes_swf[count],nodes_values[count],nodes_pages[count] , 1); 
       nodes_names[count]   = take_items[0]; 
       nodes_swf[count]   = take_items[1]; 
       nodes_values[count]   = take_items[2]; 
       nodes_pages[count]   = take_items[3]; 
       count++; 
      } 
      else 
      { 
       nodes_names[count]   = eachChild.name(); 
       nodes_swf[count]   = eachChild.attribute("swf"); 
       nodes_pages[count]   = eachChild.attribute("htmlpage");  
       nodes_values[count]   = eachChild.text(); 
       count++; 
      } 
     } 
      var _items:Array = new Array(nodes_names, nodes_swf,nodes_values,nodes_pages); 
      return _items; 
    } 
0

第一次解析XML时,您可以将数据存储在Object中,以便随后在需要时更容易/更快地检索一组属性。

如果您愿意,可以将此对象视为多维数组。

1

与Array.sortOn方法结合使用时,转换为对象也可能会有所帮助。您也可以考虑使用JSON作为传输格式;它将消除解析和转换XML的开销。

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