转换原始查询到Laravel雄辩

Question

如何该原始查询转换为Laravel雄辩的语言：

select c.name as country from country c, address ad, city ci where 
ad.id = 1 and city.id = ad.city_id and c.code = ci.country_code 

Answer 1

First link

Second link

Query Builder

DB::table("country") 
->join('city', 'city.country_code', '=', 'country.user_id') 
->join('address', 'address.city_id', '=', 'city.id') 
->select('country.name as country') 
->where('address.id', 1) 
->get(); 

Eloquent

Country::with(['city','address' => function($query){ 
    return $query->where('id', 1) 
}]) 
->select('country.name as country') 
->get(); 

Answer 2

我将修改的答案从Andrey Lutscevich雄辩部分

Country::select('country.name as country')->has('city') 
    ->whereHas('address', function ($query) 
    { 
    $query->where('id', 1); 
    }) 
    ->get(); 

查询关系存在 当访问记录的模型，你不妨基础上，以限制搜索结果的关系的存在使用has在这种情况下

WhereHas methods put "where" conditions on your has queries