如何获得最后一个记录上第二个三联接在SQL

Question

我有这样的SQL语句：

Select 
PD.PKey 
, PD.PId 
, PVDR.ProID 
FROM `TABLE1` PD 
JOIN `TABLEFACT` FACT 
     ON PD.PId = FACT.PId 
JOIN `TABLE2` PVDR 
     ON PVDR.ProId = FACT.AProId 

TABLEFACT有场PDATE这是一个日期字段。

如何过滤TABLEFACT所以只有在连接到TABLE2之前返回MAX(PDATE)？

假设MYSQL。非常感谢！

谢谢！

Answer 1

您可以使用子查询，也称为派生表，如下所示：

Select 
    PD.PKey 
    , PD.PId 
    , PVDR.ProID 
FROM `TABLE1` PD 
JOIN (SELECT MAX(PDate) as Pdate, PId 
     FROM `TABLEFACT` 
     GROUP BY PId 
    ) FACT 
    ON PD.PId = FACT.PId 
JOIN `TABLE2` PVDR 
    ON PVDR.ProId = FACT.AProId 

这是假设你想要的MAX(PDate)每个PId

如果你只想要PId与最新PDate然后使用正常子查询：

Select 
    PD.PKey 
, PD.PId 
, PVDR.ProID 
FROM `TABLE1` PD 
JOIN `TABLEFACT` FACT 
    ON PD.PId = FACT.PId 
JOIN `TABLE2` PVDR 
    ON PVDR.ProId = FACT.AProId 
WHERE FACT.PDate = (SELECT MAX(PDate) FROM `TABLEFACT`) 

Answer 2

您可以使用子查询：https://dev.mysql.com/doc/refman/5.7/en/subqueries.html

Select 
PD.PKey 
, PD.PId 
, PVDR.ProID 
FROM `TABLE1` PD 
JOIN `TABLEFACT` FACT 
     ON PD.PId = FACT.PId 
     AND 
     FACT.PDATE = (
      SELECT 
       MAX(PDATE) 
      FROM 
       `TABLEFACT` 
     ) 
JOIN `TABLE2` PVDR 
     ON PVDR.ProId = FACT.AProId