原始消息我使用分离器拆分职位在单个消息。单个消息充满了一些数据。拆分后,我想将所有消息合并到一个。但是当我这样做时,我只能得到所有职位,而不是边界XML。我怎样才能得到在我的路由Splitter AggregateStrategy
我的XML:
<order>
<firstname>Max</firstname>
<lastname>Mustermann</lastname>
<positions>
<position>
<articlename>Article 1</articlename>
<amount>1</amount>
</position>
<position>
<articlename>Article 2</articlename>
<amount>2</amount>
</position>
</positions>
</order>
我的路线:
from("activemq:orders")
.split(body().tokenizeXML("POSITION",""), new AggregatePositionsStrategy())
.enrich("direct:getArticleNumber", new addArticleNrToPositionStrategy())
.end()
.to("file://c:/temp")
的路线后,我的XML是:
<position>
<articlenumber>654321</articlenumber>
<articlename>Article 1</articlename>
<amount>1</amount>
</position>
<position>
<articlenumber>123456</articlenumber>
<articlename>Article 2</articlename>
<amount>2</amount>
</position>
新的数据被插入,但订单界丢失。我能做些什么来获取所有数据?
我AggregatePositionsStrategy的Splitter是:
public class AggregatePositionsStrategy implements AggregationStrategy {
public Exchange aggregate(Exchange exchange, Exchange response) {
if (exchange == null) {
return response;
}
if (exchange.getIn().getHeader("Artikelnummer") != null && exchange.getIn().getHeader("Artikelnummer").equals("Not Found")) {
exchange.getIn().setHeader("Artikelnummer", "Not Found");
}
if (response.getIn().getHeader("Artikelnummer") != null && response.getIn().getHeader("Artikelnummer").equals("Not Found")) {
exchange.getIn().setHeader("Artikelnummer", "Not Found");
}
String orders = exchange.getIn().getBody(String.class);
String newLine = response.getIn().getBody(String.class);
orders = orders + "\n" + newLine;
exchange.getIn().setBody(orders);
return exchange;
}
}
我知道,我只是人体的从劈裂邮件复制。但我不知道如何获得原始信息,以获取所有部分。你有好主意吗?
如果我不使用AggregateStrategy。分割后我得到原始的消息体,但没有丰富的数据。 http://camel.apache.org/splitter.html#Splitter-WhattheSplitterreturns所以必须有原始的Message体到处 – Burner 2015-01-21 09:09:50